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rjkz [21]
3 years ago
6

A cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 5 inches. The height of the cone is 15 inc

hes. Use π = 3.14. What is the relationship between the volume of this cylinder and this cone? Explain your answer by determining the volume of each and comparing them. Show all your work.

Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0
The volumes of the cone and the cylinder are equal

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Write 68.94 in word form
olga55 [171]

Answer:

sixty-eight and ninety-four hundredths

Step-by-step explanation:

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25 points need ASAP
mars1129 [50]

Answer:

68%

Step-by-step explanation:

17 divided by 25 =0.68

make the decimal into a precent

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3 years ago
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If 10% of x is 30, what is 23% of x <br> A. 33<br> B. 46<br> C. 200<br> D. 230
aliina [53]

Answer:

69

Step-by-step explanation:

I'm mathematics, the word 'of' transfers into becoming 'times or Multiply'

Therefore, the expression can be rewritten as:

10/100 of x = 30

10x / 100 = 30

Cross Multiply the equation to solve for x

10x = 100 * 30

10x = 3000

x = 3000 / 10

x = 300

(Since we gotten the value of x as 300) let's find 23% of it.

Therefore,

23% of x, ( when x is 300)

= 23/100 * 300

= 23 * 3

= 69

(Well, although that's the workable solution, the option doesn't seen to tally)

Maybe you check the source, but am certain about the Solution.

Let's keep learning, maths is fun !

3 0
3 years ago
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A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40
malfutka [58]
PART A

The given equation is

h(t) = - 16 {t}^{2} + 40t + 4

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4

We add and subtract

- 16(- \frac{5}{4} )^{2}

to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4

We again factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4

This implies that,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4

The quadratic trinomial above is a perfect square.

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4

This finally simplifies to,

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29

The vertex of this function is

V( \frac{5}{4} ,29)

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

29

PART B

When the ball hits the ground,

h(t) = 0

This implies that,

- 16 ( t- \frac{5}{4}) ^{2} +29 = 0

We add -29 to both sides to get,

- 16 ( t- \frac{5}{4}) ^{2} = - 29

This implies that,

( t- \frac{5}{4}) ^{2} = \frac{29}{16}

t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }

t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}

t = \frac{ 5 + \sqrt{29} }{4} = 2.60

or

t = \frac{ 5 - \sqrt{29} }{4} = - 0.10

Since time cannot be negative, we discard the negative value and pick,

t = 2.60s
8 0
3 years ago
Solve for x.
kumpel [21]
Divide by 1.8
x = around 35.56
6 0
3 years ago
Read 2 more answers
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