1.) 4(x+3)
Find the GCF, Greatest Common Factor, of 4x and 12.
4x=2*2*x
12=3*2*2
The greatest common factor is 4. Put this outside of the parentheses. (You would multiply the 2*2)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Solution: 4(x+3)
To check, distribute to see if it works.
4x+12
2.) 2(4r+7)
Find the GCF of 8r and 14
8r=2*2*2*r
14= -1*7*2
The greatest common factor is 2. (There is only 1 two, so you would not multiply them.)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Multiply the 2*2*r as one addend and the -1*7 as the other.
Solution: 2(4r-7)
To check, distribute to see if it works.
8r-14
Do you get it now?
3.) 5(x+7)
4.) 7(2x+1)
5.) Cannot be factored.
32x-15
Find the GCF of 32x and -15
32x: 2*2*2*2*2*x
-15: -1*5*3
Because there are no similar factors other than 1, it cannot be factored.
6.) 8(4x+3)
7.) 3(2x-3)
8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)
Answer:
<u>a</u>
Step-by-step explanation:
Given :
⇒ P (Sumit) = 1/2
⇒ P (Sujan) = 1/3
⇒ P (Rakesh) = 1/a
⇒ P (total) = 3/4
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Solving :
⇒ 1/2 × 1/3 × 1/a = 3/4
⇒ 1/6 × 1/a = 3/4
⇒ 2/12 × 1/a = 9/12
⇒ a = <u>9/2</u>
Answer:
274560
Step-by-step explanation:
We can "choose" one of the 66 athletes for the gold medal. That athlete can't win any other medals, so there are 65 athletes left.
We can then "choose" one of the 65 athletes left for the silver medal. That athlete can't win any other medals, so there are 64 athletes left.
We can then "choose" one of the 64 athletes left for the bronze medal.
That leaves us with 66 possible choices * 65 possible choices * 64 possible choices=274560 possible choices
Answer:
m=(r/n)+0.114r
Step-by-step explanation:
m=monthly payment
r=remaining amount
n=# of months remaining
