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3 years ago

What are the graph line points?!! Please Helpp!

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

4 0

Answer:

(0, 0) and (2, -4)

Step-by-step explanation:

Lapatulllka [165]3 years ago

4 0

Answer:

(2,-4) :)

Step-by-step explanation:

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Dont do QA <br> plzzzzzzzzzzzzzzzzzzzzzzzz

N76 [4]

Answer:

$(a) x^2-2x=x \times (x+2) \\\\(b) 6x^2+12x=2\times 3 \times x \times ( x + 2) \\\\(c) 3x^3 - 9x=3\times x \times (x^2 -3) \\\\(d) 4x^2 +28 x^3 = 2 \times 2 \times x \times x \times ( 1+ 7x)$

Step-by-step explanation:

To factorize, at first, do factorize all the terms then take the common terms out.

(a) $x^2-2x$

This can be written as

$x^2-2x= x\times x + 2 \times x$

Now, taking x commom from both the terms.

$x^2-2x=x \times (x+2)$

(b) $6x^2+12x$

$=2\times 3 \times x\times x + 2\times 2 \times 3 \times x$

Now, taking $2\times 3\times x$ common from both the terms, we have

$6x^2+12x=2\times 3 \times x \times ( x + 2)$

This is the required factorization.

$= 3 \times x \times x \times - 9\times x \\\\ 3x^3 - 9x=3\times x \times (x^2 -3)$

This is the required factorization.

(d) $4x^2 +28 x^3$

$= 2 \times 2 \times x \times x + 2 \times 2 \times 7 \times x \times x \times x \\\\4x^2 +28 x^3 = 2 \times 2 \times x \times x \times ( 1+ 7x)$

This is the required factorization.

7 0

3 years ago

Simply -3 3/4 divided by 2 1/2

Dima020 [189]

Answer:

$=-1\frac{1}{2}$

Step-by-step explanation:

Given the following question:

$-3\frac{3}{4} \div2\frac{1}{2}$

In order to find the answer, we first convert the mixed numbers into improper fractions. Then we use KCF (Keep, Change, Flip) and solve.

$-3\frac{3}{4} \div2\frac{1}{2}$
$-3\frac{3}{4} =12+3=-\frac{15}{4}$
$2\frac{1}{2}=2\times2=4+1=\frac{5}{2}$
$-\frac{15}{4} \div\frac{5}{2}$
$-\frac{15}{4} \times\frac{2}{5}$
$15\times2=30$
$4\times5=20$
$=-\frac{30}{20}$
$-\frac{30}{20} \div10=-\frac{3}{2}$
$-\frac{3}{2}=3\div2=-1\frac{1}{2}$
$=-1\frac{1}{2}$

Hope this helps.