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Zarrin [17]
3 years ago
6

Is a measure of how much water an air mass at a given temperature can hold.

Chemistry
1 answer:
stiv31 [10]3 years ago
7 0

relative humidity is a measure of how much water an air mass at a given temperature can hold.

<u>Explanation:</u>

When a quantity of air at a supplied temperature exists the highest volume of water vapor, the air is considered to be saturated. The relative humidity is the water-vapor content of the air corresponding to its content at fullness.

Relative humidity can be described as the quantity of water vapor in air at a provided temperature related to what that air could endure at that temperature. We can thus adjust the relative humidity of an air bundle by either raising or lowering the volume of water vapor in the parcel OR by boosting or reducing the temperature of the air mass.

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Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
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Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

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