In an electron dot diagram of propane (C3H8), how many double bonds are present?
2 answers:
Answer : The number of double bonds present in propane is, Zero.
Explanation :
Lewis-dot structure : Lewis-dot structure shows the bonding between the atoms of a molecule and also shows the unpaired electrons present in the molecule.
Carbon has '4' valence electrons and hydrogen has '1' valence electrons.
The total number of valence electrons in = 3(4) + 8(1) = 20
In the given molecule propane, there is a single bond present between the carbon-carbon atom and carbon-hydrogen atom.
According to the Lewis-dot structure, the number of double bonds present in propane is, Zero.
The Lewis-dot structure is shown below.
Answer:- none
Explanations:- For naming hydrocarbons we use the suffix -ane, -ene and -yne.
-ane is used when we have only single bonds between all carbons. -ene is used if there is any double bond between two carbons and the -yne is used if there is any triple bond between two carbons.
The given name of the compound is propane. It ends at -ane and so it's an alkane and must have single bonds between all the carbons it has. So, there are zero double bonds present in .
This is also clear from the below lewis dot structure of the compound.
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