All categories

3 years ago

Overfatness in babies is discouraged because it may:

Chemistry

2 answers:

matrenka [14]3 years ago

3 0

I think it would be A) cause an increase in the number of fat cells.

s344n2d4d5 [400]3 years ago

3 0

Answer:

Option C. cause creeping obesity later in life.

Explanation:

Overfatness in babies is discouraged because it encourages obesity in the later years of the child's life. In addition, it is because some propensity to gain excess weight might be inbuilt within the child's system. Furthermore, this results in some genetic mutation that might result in cells accepting more than the fat content they are supposed to take.

You might be interested in

For a reaction 2A + B 2C, with the rate equation: Rate = k[A]2[B]

In-s [12.5K]

For reaction

2 A + B ------------> 2 C

Rate = K [ A ]² [ B ]

 the order with respect to A is 2 and the order overall is 3.

hope this helps!

3 0

3 years ago

Compare the atomic sizes of sodium and magnesium. Explain.

mihalych1998 [28]

Answer:

Sodium atom is larger than Magnesium atom.

Explanation:

Looking at the electronic configurations of Sodium and Magnesium:

$_{11}Na: 1s^2 2s^2 p^6 3s^1\\\\_{12}Mg : 1s^2 2s^2 p^6 3s^2$ ,

we can see that they both have their valence electrons in the 3rd shell.

But because Magnesium has a higher nuclear charge of +12 because of its 12 protons than that of Sodium's +11, the nucleus of Magnesium attracts its outer electrons more strongly than Sodium does. This makes the Magnesium atom smaller.

5 0

2 years ago

For the question(s) that follow, consider the following balanced equation. Mg3N2(s) + 6H2O(l) → 3Mg(OH)2(s) + 2NH3(g) How many g

Slav-nsk [51]

Answer:

93 g of $H_{2}O$ are needed to produce 150 g of $Mg(OH)_{2}$

Explanation:

1. Writhe the balanced equation given by the problem:

$Mg_{3}N_{2}(s)+6H_{2}O(l)=3Mg(OH)_{2}(s)+2NH_{3}(g)$

2. Then use the stoichiometry of the reaction to calculate the mass of $H_{2}O$ that is needed to produce 150g of $Mg(OH)_{2}$ :

It is important to take in account the molar mass of the $Mg(OH)_{2}$ and the $H_{2}O$ for the calculations.

Molar mass of the $Mg(OH)_{2}$ = 58.3g

Molar mass of the $H_{2}O$ = 18g

$150gMg(OH)_{2}*\frac{1molMg(OH)_{2}}{58.3gMg(OH)_{2}}*\frac{6molesH_{2}O}{3molesMg(OH)_{2}}*\frac{18gH_{2}O}{1molH_{2}O}=93gH_{2}O$

6 0

3 years ago

In 1961, the reference for the atomic mass unit (amu or u) was changed from naturally occurring oxygen with a value of 16.000 u

vovangra [49]

To determine the mass of an atom in terms of atomic mass unit (a.m.u.) the standard should have the fixed mass otherwise the calculated mass of the other atoms will get error. Initially oxygen was used as the reference standard for the calculation of other atoms mass. But after the invention of different isotopes of oxygen i.e. $O^{17}$ and $O^{18}$ which ratios with respect to $O^{16}$ is 1.002 the mass of standard oxygen became unstable. Thus the mass of the new atom have error. Thus in 1961 the standard reference is canged to carbon-12. After that onward the mass of the other atoms are measured with respect to carbon.

3 0

3 years ago

Serotonin is a compound that conducts nerve impulses in the brain. it contains 68.2 mass percent c, 6.86 mass percent h, 15.9 ma

Artemon [7]

C10H12N2O First, lookup the atomic weights of C, H, N, and O Atomic weight of Carbon = 12.0107 Atomic weight of Hydrogen = 1.00794 Atomic weight of Nitrogen = 14.0067 Atomic weight of Oxygen = 15.999 Now determine the ratio of atoms of each element by dividing their mass percentage by their atomic weights. Carbon = 68.2 / 12.0107 = 5.67827 Hydrogen = 6.86 / 1.00794 = 6.805961 Nitrogen = 15.9 / 14.0067 = 1.135171 Oxygen = 9.08 / 15.999 = 0.567535 Now determine a simple integer ratio of small integers that closely approximates the ratio of relative molar amounts. 5.67827 : 6.805961 : 1.135171 : 0.567535 Going to first divide all values by 0.567535 (picked because it's the smallest in the above ratios) getting 10.005 : 11.992 : 2.000 : 1 These numbers are all extremely close to integers so it looks like the empirical formula for Serotonin is C10H12N2O Let's compute the molar mass of the empirical formula 10 * 12.0107 + 12 * 1.00794 + 2 * 14.0067 + 15.999 = 176.2 g/mol Since that calculated molar mass matches the desired target, we're done. If the calculated mass was smaller, or the desired mass was larger (like 352 g/mol) we would have multiplied the number of atoms by the appropriate factor. But that's not needed, so the molecular formula for Serotonin is C10H12N2O

6 0

3 years ago