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stich3 [128]
3 years ago
8

Two solid spheres of radius R made of the same type of steel are placed in contact. The magnitude of the gravitational force the

y exert on each other is F1. When two other solid spheres of radius 3R made of this steel are placed in contact, what is the magnitude of the grav force that they exert on each other?
A) F1
B) 3F1
C) 9F1
D) 81F1
Physics
1 answer:
dimulka [17.4K]3 years ago
3 0
F1 = G * m*m / [2r]  ^2 = G * m^2 / 4r^2

Given the the mass is proportional to the volume and the volume is proportional to r^3, the mass of each big sphere is  3^3 = 27 times the mass of the small spheres. And the distance between the centers is 3r + 3r = 6r

F2 = G * [27m * 27m]/* [6r]^2 = G* 27^2 m^2 / 36r^2 = 81 G*m^2 / 4r^2 = 81*F1

Therefore, F2 = 81F1

Answer: option D) 81F1.
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r-ruslan [8.4K]

Answer:

Matter can be changed, but not created or destroyed.

Explanation:

Matter can change for through physical and chemical changes, though this happens, matter is conserved. The same amount of matter exists before and after the change.

3 0
2 years ago
A particle leaves the origin with a speed of 3 106 m/s at 38 degrees to the positive x axis. It moves in a uniform electric fiel
Salsk061 [2.6K]

Answer:

If the particle is an electron E_y = 3.311 * 10^3 N/C

If the particle is a proton, E_y = 6.08 * 10^6 N/C

Explanation:

Initial speed at the origin, u = 3 * 10^6 m/s

\theta = 38^0 to +ve x-axis

The particle crosses the x-axis at , x = 1.5 cm = 0.015 m

The particle can either be an electron or a proton:

Mass of an electron, m_e = 9.1 * 10^{-31} kg

Mass of a proton, m_p = 1.67 * 10^{-27} kg

The electric field intensity along the positive y axis E_y, can be given by the formula:

E_y = \frac{2 m u^2 sin \theta cos \theta}{qx} \\

If the particle is an electron:

E_y = \frac{2 m_e u^2 sin \theta cos \theta}{qx} \\

E_y = \frac{2 * 9.1 * 10^{-31} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\

E_y = 3311.13 N/C\\E_y = 3.311 * 10^3 N/C

If the particle is a proton:

E_y = \frac{2 m_p u^2 sin \theta cos \theta}{qx} \\

E_y = \frac{2 * 1.67 * 10^{-27} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\

E_y = 6.08 * 10^6 N/C

8 0
3 years ago
If two proton approach each other with speed of 400m\s and 450m\s respectively what is the total momentum of the two particle sy
lilavasa [31]

Answer: 83.65\times 10^{-27}\ kg.m/s

Explanation:

Given

The velocities of the protons are 400 m/s and 450 m/s

Mass of the Proton is m=1.673\times 10^{-27}\ kg

Since they travel in the opposite direction, therefore, their momentum cancels out each other.

Momentum is the product of mass and velocity

\therefore m(450-400)\\\Rightarrow 1.673\times 10^{-27}\times 50\\\Rightarrow 83.65\times 10^{-27}\ kg.m/s

The direction of momentum is in the direction of proton having 450 m/s velocity.

7 0
2 years ago
Newton’s first law says that a body will remain in a state of rest, or move in a straight line at a constant speed, unless it is
dangina [55]

Answer:

Gravity

Explanation:

The Hubble is continually attracted to the earth due to the action of gravity. Therefore, it is thanks to gravity that the space telescope is kept in orbit. Without him, the direct motion generated by inertia would take him out of course. Gravity slows it down and keeps it in the curved path of its orbit around the Earth.

7 0
2 years ago
Young's double slit experiment is one of the classic tests for the wave nature of light. In an experiment using red light (λ = 6
Marianna [84]

Answer:

The separation distance between the slits is 16710.32 nm.

Explanation:

Given that,

Wavelength = 641 nm

Angle =4.4°

(a). We need to calculate the separation distance between the slits

Using formula of young's double slit

d\sin\theta=m\lambda

d=\dfrac{m\lambda}{\sin\theta}

Where, d = the separation distance between the slits

m = number of order

\lambda =wavelength

Put the value into the formula

d=\dfrac{2\times641\times10^{-9}}{\sin4.4}

d=0.00001671032\ m

d=16710.32\ nm

Hence, The separation distance between the slits is 16710.32 nm.

3 0
3 years ago
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