Answer:
(a) 348.4 m
(b) 256.7 m/s
(c) 127.2 m/s^2
Explanation:
(a) at t = 4 s
x = 2.3 x 4 + 5.3 x 4 x 4 x 4
x = 348.4 m
(b) The derivative of displacement function gives the value of instantaneous velocity.
So, v = dx / dt = 2.3 + 5.3 x 3 x t^2
v = 2.3 + 15.9 t^2
Put t = 4 s
So, v = 2.3 + 15.9 x 4 x 4
v = 256.7 m/s
(c) The derivative of velocity function with respect to time gives the value of instantaneous acceleration.
So, a = dv / dt = 5.3 x 3 x 2 x t
a = 31.8 t
Put t = 4 s
a = 31.8 x 4 = 127.2 m/s^2
Answer: D (doubled)
According to ohm's law
I = V/R ,
V = IR ; R = constant and V is doubled
From the equation
V is directly proportional to the current, and it is given that R is constant ;
2V = 2I. R since R = constant
Hence I is doubled.
Answer: Water is absorbed in the intestine through gradient transport. The correct option is E.
Explanation:
Absorption of water in the mammalian intestines occurs largely on the small intestine through a transport mechanism known as osmosis. Osmosis is the movement of water molecules, through a semi permeable membrane, from the region of lower solute concentration into higher solute concentration to attain an equilibrium.
For water molecules to be absorbed from the lumen into the bloodstream, it's dependent on sodium absorption. This follows the following steps:
-sodium is absorbed by co transport with glucose and amino acids.this aids to move sodium from lumen into the enterocyte.
- Rapid exportation of absorbed sodium through sodium pimps from the enterocyte.
- As sodium is pumped out of cells an osmotic gradient is formed across apical cell membrane, this helps to osmotically drive water across the epithelium. Therefore water is absorbed in the intestine through the osmotic gradient created by sodium absorption. I hope this helps. Thanks.
Answer:
electric current is derived unit.
Explanation:
According to the definition of electric current, it appears to be a derived quantity. Charge on the other hand seems more fundamental than electric current.
Answer:
Explanation:
Given that
Superelation= 0.08ft/ft
Given curve= u•
Curve junction factor= 0.13
DR= 5729.57795
R = 5729.57795/D
R = 5729.57795/4
R = 1432.4ft
c + f = V^2/gG
0.08 + 0.13 = V^2 / (32*1432.4)
V^2 = 9625.728 or V = 98 ft/sec
The designed speed for a project considered is a minimum value which means the highway design elements will meet or exceed the standards for the design speed. The maximum safe speed under normal condition is significantly greater than design speed
