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1 year ago

Explain 4 factors affecting centripetal acceleration

Physics

1 answer:

Anna11 [10]1 year ago

4 0

Answer:

it's speed

mass of the object

and the radius of the circle

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2) As a freshman in college, you enter a classroom hall believing it is Physics 101 and sit down. The professor says, "During th

Valentin [98]

No because you don’t learn about synthetic inventions yet in your first year

3 0

3 years ago

A guyot is ________. A. any portion of the ocean floor that is topographically higher than surrounding sea floor B. an extinct o

Maksim231197 [3]

Answer:

c.an extinct oceanic hot-spot volcano that has subsided below sea level

Explanation:

- Marine geology defines a guyot as an isolated underwater volcanic mountain with a flat top more than 200m below the surface of the sea.

-The flat top is due to years of wave erosion.

-Guyots can form a chain of seamounts as the ocean plate of the Earth's crust moves slowly over a hot spot that remains stationary beneath the plate.

6 0

2 years ago

If Juan upgrades from a sports car to a large truck, what will happen to the

Brrunno [24]

Answer:

The force must increase

Explanation:

According to newton's second law "force is the product of mass and acceleration".

Force = mass x acceleration

Now, the mass of the sports car is lesser compared to that of the truck. Therefore, to take both automobiles to the same speed, enough force must be applied by the engine of the truck.

There must be an increase in the force in order to make both automobiles attain the same speed.

5 0

2 years ago

A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re

fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

$PV=nRT$

For a gas

$P_{1}V_{1}=nRT_{1}$

Where, P = pressure

V = volume

T = temperature

Put the value in the equation

$10\times V=nR\times286$ ....(I)

When the temperature of the gas is increased

Then,

$P_{2}V_{2}=\dfrac{n}{2}RT_{2}$ ....(II)

Divided equation (I) by equation (II)

$\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}$

$\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}$

$P_{2}=\dfrac{10\times368}{2\times286}$

$P_{2}= 6.433\ atm$

$P_{2}=6.4\ atm$

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

4 0

2 years ago

Two spacecraft are both 10 million kilometers from a star. The total power output of the star is 4 x 1025 W. Spacecraft 1 has a

Ksenya-84 [330]

The concept of power is given by the relationship between intensity and area, that is to say that power is defined as

$P = A*I$

Our values are given under the condition of,

$r_1 = 18m$

$r_2 = m$

The power is proportional to the Area, and in turn, we know that the Area of a circle is the product between $\pi$ times the radius squared, therefore the power is proportional to the radius squared.