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kati45 [8]
3 years ago
11

Calculate the mean, median, and mode of the following set of data. Round to the nearest tenth. 3, 15, 3, 3, 1, 11, 2, 8, 3, 7, 1

5
Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
The mode is 3. The median is 3. The mean is 6.45 and rounded to the nearest tenth is 6.5. So the mean is 6.5.
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For every 1 litre of water used to make a medicine, 193ml of sucrose and 61ml of saline solution are used. Express the amount of
Brilliant_brown [7]
<h3>Answer is the ratio 1000:193:61</h3>

Explanation

1 liter = 1000 mL

For every 1000 mL of water, we need 193 mL of sucrose and 61 mL of saline solution.

The ratio is therefore 1000:193:61

We cannot simplify this ratio any further because the GCF of those three terms is 1.

A quick way to see this is to look at how 1000 = (2*5)^3 has prime factors 2 and 5, but 2 nor 5 are factors of 193 and 61. So only 1 is a factor of all three values 1000, 193, 61

7 0
3 years ago
What is the domain of the function F(x) = 4 cos(2x+1)?
Veseljchak [2.6K]

Answer:

Domain: (-inf, inf)

Range: [-4,4]

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3 years ago
Use an algebraic rule to describe a translation right 4 units and down 2 units.
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3 years ago
Math help What are the solutions​
Westkost [7]

Answer:

x² - 4x + 12

Step-by-step explanation:

x=2+2.82843i

x=2−2.82843i

6 0
2 years ago
50 PTS ANSWER ALL &lt;3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
2 years ago
Read 2 more answers
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