Ask question

Ask question

All categories

3 years ago

11

Calculate the mean, median, and mode of the following set of data. Round to the nearest tenth. 3, 15, 3, 3, 1, 11, 2, 8, 3, 7, 1

5

1 answer:

zubka84 [21]3 years ago

6 0

The mode is 3. The median is 3. The mean is 6.45 and rounded to the nearest tenth is 6.5. So the mean is 6.5.

You might be interested in

For every 1 litre of water used to make a medicine, 193ml of sucrose and 61ml of saline solution are used. Express the amount of

Brilliant_brown [7]

<h3>Answer is the ratio 1000:193:61</h3>

Explanation

1 liter = 1000 mL

For every 1000 mL of water, we need 193 mL of sucrose and 61 mL of saline solution.

The ratio is therefore 1000:193:61

We cannot simplify this ratio any further because the GCF of those three terms is 1.

A quick way to see this is to look at how 1000 = (2*5)^3 has prime factors 2 and 5, but 2 nor 5 are factors of 193 and 61. So only 1 is a factor of all three values 1000, 193, 61

7 0

3 years ago

What is the domain of the function F(x) = 4 cos(2x+1)?

Veseljchak [2.6K]

Answer:

Domain: (-inf, inf)

Range: [-4,4]

6 0

3 years ago

Use an algebraic rule to describe a translation right 4 units and down 2 units.

Harlamova29_29 [7]

Do you have any options to pick from

4 0

3 years ago

Math help What are the solutions

Westkost [7]

Answer:

x² - 4x + 12

Step-by-step explanation:

x=2+2.82843i

x=2−2.82843i

6 0

2 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

2 years ago

Read 2 more answers