f(x)g(x) = 9x² + 10x - 16
<u>Step-by-step explanation:</u>
Step 1:
Given f(x) = 3x - 4 × 2 + 6x and g(x) = 5x + 2 × 2 - 3x
f(x) = 9x - 8
g(x) = 2x + 4
f(x)g(x) = (9x - 8)(2x + 4)
= 18x² + 36x - 16x -32
= 18x² + 20x - 32
= 9x² + 10x - 16
M = 21 - R is our equation. Plug your value of 12 into the equation for R.
M = 21 - 12.
M = 9.
Greg would have 9 magazines left after reading 12 of them
(1/2)^2 = 1/4
2-2/3 = 6/3 - 2/3 = 4/3
OK so:
(1/2)^2 - 6(2-2/3) = 1/4 - 6(4/3)
= 1/4 - 8
= 1/4 - 32/4
= -31/4
Yes they are the same. The number on the right just has an extra zero. You can add an infinite amount of zeros to the end of a number without changing it's value.
A fraction with a numerator that is greater than or equal to the denominator is known as an improper fraction.
