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shepuryov [24]
3 years ago
7

I just need help on this.​

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
8 0

Answer:

Step-by-step explanation:

From the problem statement:

"I am less than one-half"

This means that the number is less than \frac{1}{2}, or 0.50

"but greater than four tenths"

This means that the number is greater than \frac{4}{10}, or 0.40

"I am a decimal with the digit 2 in my hundredths place"

This means that the number follows the format 0.x2, so we just need to figure out what x is. We know that the number is between 0.40 and 0.50, so the number in this case would be 0.42

Arturiano [62]3 years ago
4 0

Answer:

.42 is an answer that will work.

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In the video, the water level was 15 milliliters before adding the chain, and 20 milliliters after adding the chain. When I weig
mr_godi [17]

Answer:

  • 39.7%

Explanation:

<u />

<u>1. First find the density of your chain</u>

  • Density = mass / volume

  • Volume = displaced water volume

                      = Volume of Final level of water - initial level of water

                     = 20 ml - 15 ml = 5 ml

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  • Density = 66.7g / 5 ml = 13.34 g/ml

<u />

<u>2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:</u>

Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.

Calling x the amount of gold, then the amount of other metals is 66.7 - x:

        \dfrac{19.3\cdot x+9.7\cdot (66.7-x)}{66.7}=13.34

       19.3x+635.66-9.7x=889.778

      9.6x=254.118\\\\x=26.47

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3 years ago
What is 33 divided by 2244
olchik [2.2K]

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Step-by-step explanation:

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Answer:

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The number of rookie cards in a variety pack of baseball cards is normally distributed with a mean of 3 cards and the standard d
Sergio039 [100]

Answer:

z = \frac{2-3}{\frac{1}{\sqrt{10}}}=-3.163

z = \frac{4-3}{\frac{1}{\sqrt{10}}}=3.163

P(-3.163

P(-3.163

So then we will expect 9.98 packages between 2-4 rookie cards in the sample of 10

Step-by-step explanation:

Let X the random variable that represent the number of rookie cards of a population, and for this case we know the distribution for X is given by:

X \sim N(3,1)  

Where \mu=3 and \sigma=1

We select a sample size of n = 10 variety packs and we want to find this probability:

P(2

We can use the z score formula given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

We can find the z score for 2 and 4 and we got:

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z = \frac{4-3}{\frac{1}{\sqrt{10}}}=3.163

So we can find the probability with this difference

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And using the normal standard distirbution or excel we got:

P(-3.163

So then we will expect 9.98 packages between 2-4 rookie cards in the sample of 10

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