A galaxy whose stars are arranged in a disk with arms that surround a central bulge is a ____

Do two bodies have to be in physical contact to exert a force upon one another?

Mekhanik [1.2K]

The correct answer to the statement " Do two bodies have to be in physical contact to exert a force upon one another " is:

No, the gravitational force is a field force and does not require physical contact to exert

a force.

The correct option is a.

<h3>Why two bodies do not have to be in physical contact to exert a force upon one another as a result of gravitational force.</h3>

It has been practically proven that two bodies can exert a force upon each other even if there is no physical contact between them. This can as a result of gravity.

That being said, a magnetic attraction can also exert a force between two different bodies upon one another.

So therefore, it can be deduced from above that two different bodies do not have to be in physical contact before they exert a force upon one another.

Read more on force:

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3 0

2 years ago

Asteroids orbit the sun like planets do. why are aseroids not consideed to be planets?

aleksandr82 [10.1K]

Answer:

asteroids are broken pieces of rock and are small compared to actual planets also asteroids travel in "belts" and not there own course

Explanation:

that was my best suggestion

5 0

4 years ago

An ion's position vector is initially r = 8.0 i - 4.0 j + 3.0 k, and 8.0 s later it is r = 4.0 i + 8.0 j - 6.0 k, all in meters.

tangare [24]

The average velocity = Displacement between two points/ Time taken for that displacement

In this case An ion's position vector is initially r = 8.0 i - 4.0 j + 3.0 k, and 8.0 s later it is r = 4.0 i + 8.0 j - 6.0 k

So, displacement = 4.0 i + 8.0 j - 6.0 k - (8.0 i - 4.0 j + 3.0 k)

= -4.0 i + 12.0 j - 9.0 k

So velocity, V = (-4.0 i + 12.0 j - 9.0 k)/8

= -0.5 i + 1.5 j - 1.125 k

So average velocity during 8 seconds = -0.5 i + 1.5 j - 1.125 k

3 0

3 years ago

A jetliner rolls down the runway with constant acceleration from rest, it reaches its take off speed of 250 km/h in 1 min. What

nlexa [21]

Answer:

Acceleration, $a=14970.05\ km/h^2$

Explanation:

Given that,

Initially, the jetliner is at rest, u = 0

Final speed of the jetliner, v = 250 km/h

Time taken, t = 1 min = 0.0167 h

We need to find the acceleration of the jetliner. The mathematical expression for the acceleration is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{250}{0.0167}$

$a=14970.05\ km/h^2$

So, the acceleration of the jetliner is $14970.05\ km/h^2$ . Hence, this is the required solution.

3 0

4 years ago

A 26.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 11.0 m th

frozen [14]

Answer:

18 m/s

Explanation:

Force is given by mass × acceleration

F = ma

a = F/m

For the first 11.0 m, there is no friction. Hence, the constant force is applied fully on the crate. The acceleration is

a = 225/26.0 m/s²

By the equation of motion, v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance travelled.

Using the values for the first part of the motion,

v² = 0² + 2 × 8.65 × 11.0

v = 13.8 m/s

This is the initial velocity for the second part of the motion. This part has friction of coefficient 0.20.

The frictional force = 0.20 × weight = 0.20 × 26.0 × 9.8 = 50.96 N

The effective force moving the crate in the second motion = 225 - 50.96 N = 174.04 N

This gives an acceleration of 174.04/26.0 = 6.69 m/s².

Using parameters for the equation of motion, v² = u² + 2as

v² = 13.8² + 2 × 6.69 × 10 = 324.24

v = 18 m/s

8 0

4 years ago

A galaxy whose stars are arranged in a disk with arms that surround a central bulge is a _____ galaxy.