Using the formula F=ma
500N=50kg (a)
a= 10 m/s^2
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The rank is : 
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We need to rank the objects according to the magnitude of their momentum.
We know momentum ,
{ here m is mass and v is velocity }
Momentum of object A , 
Momentum of object B , 
Momentum of object C , 
Now, we can rank them in order of their magnitude of momentum .
.
Hence, this is the required solution.
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Momentum
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Answer:
1)a. It is constant the whole time the ball is in free-fall.
2)b. = 14 m/s
3) e. = 19.6 m/s
Explanation:
1) given that the only force acting on the ball is gravity, gravity acts along the vertical axis. Since no other force acts on the ball then the horizontal velocity will remain constant all through the flight since there is no horizontal force acting on the ball.
2) speed = distance/time
horizontal distance = 56m
Time = 4 seconds
Speed = 56m/4s = 14m/s
3) acceleration due to gravity g = 9.8m/s^2
Initial vertical velocity = u
Final vertical velocity = v = -u
Using the law of motion;
v = u + at
a = acceleration = -g = -9.8m/s^2
t = time of flight = 4
Substituting the values;
-u = u - 4(9.8)
-2u = -4(9.8)
u = -4(9.8)/-2
u = 2(9.8) = 19.6 m/s
Initial vertical velocity = u = 19.6 m/s
It is true
I hope this helps