All categories

3 years ago

Is possible to form a triangle with the side lengths. 2 mm, 2 mm, 8 mm?

Mathematics

1 answer:

PIT_PIT [208]3 years ago

3 0

Answer: Some-what. 8 mm on the bottom and 2 mm on the two sides. The triangle is called Isosceles triangle

Step-by-step explanation:

You might be interested in

Nina goes to the neighborhood store to buy 14 rolls of toilet paper. If she spent $20.02 in all for her purchase, how much does

lilavasa [31]

Answer:

Each roll is $1.43.

Step-by-step explanation:

20.02 ÷ 14 = 1.43.

1.43 × 14 = 20.02.

3 0

3 years ago

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$

$A2=(4)(x)=4x\ in^2$

$A3=(x)(7)=7x\ in^2$

$A4=(4)(7)=28\ in^2$

The total area of the second rectangle is the sum of the four areas

$A=A1+A2+A3+A4$

State the product of (x+4) and (x+7) as a trinomial

$(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28$

Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?

we know that

The area of the second rectangle is equal to

$A=A1+A2+A3+A4$

For x=2 in

substitute the value of x in the area of each portion

$A1=(2)(2)=4\ in^2$

$A2=(4)(2)=8\ in^2$

$A3=(2)(7)=14\ in^2$

$A4=(4)(7)=28\ in^2$

$A=4+8+14+28$

$A=54\ in^2$

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

$A(x)=x^{2} +11x+28$

For x=2 in

substitute and solve for A(x)

$A(2)=2^{2} +11(2)+28$

$A(2)=4 +22+28$

$A(2)=54\ in^2$ ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0

3 years ago

If CB 1 AB and mA = 60, what is the measure of C?

Yanka [14]

Answer:

The answer should be D. 120 degrees

5 0

3 years ago

4 x 2/4 as a mixed fraction

aliina [53]

4 x 2/4

2/4 can be reduced to 1/2

Now you have 4 x 1/2

Multiply 4 by 1 then divide by 2:

4 x 1 = 4

4/2 = 2

The answer is 2

5 0

2 years ago

Rachel recorded the number of calls she made at work during the week:

Dmitry [639]

The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.

<h3>What is the chi-squared test statistic?</h3>

Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.

The formula for the chi-squared test statistic is;

$\sum \frac{(O_i-E_i)^2}{E_i } \\\\$

Where,

$\rm O_i$ is the observed value

$\rm E_i$ is the expected value

The chi-square test statics is;

$\rm( \frac{18-18}{18} )^2 +( \frac{14-18}{18} )^2 + (\frac{24-18}{18} )^2+( \frac{16-18}{18} )^2 \\\\ 0+ \frac{16}{18}+ \frac{36}{18} +\frac{4}{18}\\\\ \frac{56}{18} \\\\ 3.11$

Hence, the chi-squared test statistic will be 3.11.

To learn more about the chi-squared test statistic refer;

brainly.com/question/14082240

#SPJ1

5 0

2 years ago