V57 v3 is Keats becuase it’s math and not why it’s not math it’s math just holy math with gif
Answer:
3500,00 (2 multiply by 6,75%)
3500,00 (2 multiply by 6,75 divide by 100)
3500,00 ( 2 multiply by 0,0675)
3500,00 multiply by 0,135
= R472,50
1) Answer: x = 9
<u>Step-by-step explanation:</u>
Same Side Interior Angles are supplementary
15 + 5x + 14x - 6 = 180
19x + 9 = 180
19x = 171
x = 9
***************************************************************
2) Answer: x = 9
<u>Step-by-step explanation:</u>
Corresponding Angles are congruent
13x - 7 = 11x + 11
2x = 18
x = 9
***************************************************************
3) Answer: x = -10
<u>Step-by-step explanation:</u>
Alternating Interior Angles are congruent
90 = x + 100
-10 = x
***************************************************************
3) Answer: x = 7
<u>Step-by-step explanation:</u>
Alternating Exterior Angles are congruent
17x + 1 = 120
17x = 119
x = 7
Answer:
2s+5p=40
Step-by-step explanation:
s=sodas
p=popcorn
you can plug in 0 for s or for p to see how many of the other she can get (if you plug in 0 for s you see she can get 8 popcorns, if you plug in 0 for popcorn, she can buy 20 sodas)
In this current scenario,
Probability of passing, p = 65% = 0.65
Then,
Probability of not passing, q = 1-p = 1-0.65 = 0.35
Part (a): When 15 people are tested
(i) Number of people expected to pass
This is 65% of the 15 people tested. That is,
Number of people expected to pass = 0.65*15 = 9.75. This is rounded downwards as upward rounding will violate the 65% criteria.
Therefore,
Number of people expected to pass = 9 people.
(ii) Probability that 11 people are expected to pass the test
p(x=11) = [15Cx]*p^x*q^(15-x) = [15C11]*0.65^11*0.35^(15-11) = 0.1792 ≈ 17.92%
Part (b): Teenager determined to pass the test no matter how many times
(i) Probability that he passes the test the third time
This means that he will fail the first and second time. That is,
Probability pf passing the third time = q*q*p = 0.35*0.35*0.65 = 0.079625 = 7.9625%
(ii) Number of trials it takes to pass
This is a case of mathematical expected, E, that it takes before first occurrence of success. Normally,
E = 1/p
Substituting;
E = 1/0.65 = 1.54 ≈ 2
Therefore, at least two trials will be required.
