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Aloiza [94]
3 years ago
14

I REALLY NEED HELP PLEASEEE!!! I'LL GIVE BRAINLIEST! PLEASE HELP!

Mathematics
1 answer:
marishachu [46]3 years ago
4 0

Answer:

I think the answer would be B.

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A packet of crisps contains 50g. If a “new size” packets contain 15% more, how many grams of crisps are in the “new size” packet
Agata [3.3K]
To solve this, you’d multiply 50 by 1.15 to get 57.5 grams of crisps.
4 0
3 years ago
Number lines for 43.586 to the nearest tenths, hundredths , ones
kvasek [131]
Tenths 43.5
hundredths 43.60
ones 44
4 0
3 years ago
Sis In order to identify the zeros of the function, a student factored the cubic function ()=−−f of , open x close , equals , x
creativ13 [48]

Answer:

f(x)=x(x-5)(x+2)

Step-by-step explanation:

Since the steps of the factorization of the polynomial f(x) is not given, I will proceed to give the correct factorization of f(x).

f(x)=x³-3x²-10x

First, we factor out x since it is a common term.

f(x)=x(x²-3x-10)

Next, we factorize the quadratic expression x²-3x-10.

f(x)=x(x²-5x+2x-10)

f(x)=x(x(x-5)+2(x-5))

f(x)=x(x-5)(x+2)

The correct factorization of the polynomial f(x)=x³-3x²-10x is: f(x)=x(x-5)(x+2)

7 0
3 years ago
Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

  A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

 the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

 median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

   the nonparallel sides

∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

  midpoint of RS  

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0
3 years ago
1) B. Which method of finding the distance is<br><br> the best? Explain
sveticcg [70]

Answer and Step-by-step explanation:

Distance is the numerical measurement to find the space or interval between two objects. Distance also refers to physical length. Point x to point y  distance is denoted as |xy|

There are many ways to find out the distance, distance between two objects or two points. The efficient way of finding the distance between two points is given below. Mathematically, the distance between two points on a coordinate plane can be determined by using the distance formula, which is:

                                                 d =√((x2-x1)2+(y2-y1)2),

Where (x1, y1) and (x2, y2) coordinates, and d is the distance.

The middle point between these two points is known as midpoint and can find out by using the formula

Midpoint = a + b /2.

The distance between two points number line can also be calculated by using the formula:

AB =|b –a| or |a-b|.

3 0
3 years ago
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