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Novosadov [1.4K]
4 years ago
5

I DO

Mathematics
1 answer:
lutik1710 [3]4 years ago
5 0
A. 333.45 square inches
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JL=83. if Jk=5x-4 &amp; KL=3x-1. <br> Then X=?
DIA [1.3K]

<em>Answer:</em>

<em>The answer is 83</em>

<em />

<em>Hope this helps:3</em>

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4 0
4 years ago
what are the coordinates of the orthocenter of △ABC with vertices at A(1, 2), B(1, 6), and C(5, 6)?
iren2701 [21]
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This should help for future problems
<span>https://www.mathportal.org/calculators/analytic-geometry/triangle-calculator.php</span>
6 0
3 years ago
Read 2 more answers
What is an imaginary number?
trapecia [35]

An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, which is defined by it's property i² = −1. The square of an imaginary number bi is −b². For example, 5i is an imaginary number, and it's square is −25.

8 0
3 years ago
Find the distance between the points given.<br><br> (-3, 2) and (9, -3)<br><br> √(61)<br><br> √(37)
cricket20 [7]

Answer:

d=13.

Step-by-step explanation:

d=\sqrt{(x_{2}-x_{1} ) ^{2} +(y_{2}-y_{1} ) ^{2}}

From question statement, x_{1} =-3   ,x_{2} =9

y_{1} =2  ,y_{2} =-3

put above values in the distance formula,we obtain

d=\sqrt{(9-(-3))^{2}+(-3-2)^{2}}

d=\sqrt{(12)^{2}+(-5)^{2}}

d=\sqrt{144+25}

d=\sqrt{169}

d=13


8 0
3 years ago
Pollution Rates Assignment
stepan [7]

Answer:

1. a) 4.8 lb

I) 8%

II) 0.384 lb

2. a) 12.5 lb

I) 8%

II) 1 lb

Step-by-step explanation:

Let's begin by listing out the given variables:

mass of pesticide (m) = 12 lb,

40WP (40 weight percent) means the active ingredient comprises 40% of the total mass of the pesticide

a) amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 12 * 40% = 12 * 0.4

x = 4.8 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 4.8 * 8% = 4.8 * 0.08

z = 0.384 lb

2. Let's list out the variables given, we have:

mass of pesticide = 25 lb, weight percent of active ingredient = 50% = 0.5

amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 25 * 0.5

x = 12.5 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 12.5 * 8% = 12.5 * 0.08

z = 1 lb

7 0
4 years ago
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