Answer:
where is the option I can't see plz give the option first the I try to give answer
Answer: The molecular formula will be 
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 40.0 g
Mass of O = 53.3 g
Mass of H = 6.66 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of O =
Moles of H =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For O =
For H = 
The ratio of C : O : H = 1: 1: 2
Hence the empirical formula is
The empirical weight of
= 1(12)+1(16)+2(1)= 30g.
The molecular weight = 60 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=
Had to look for the options and here is the answer. The concentration of glucose carriers in which the glucose concentration is being decreased to zero is 400. This level is already classified as above normal of the rate of glucose concentration. Hope this helps.