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stiv31 [10]
3 years ago
12

From the list below, determine which properties are for compounds. I. It takes a large amount of energy to separates the element

s of a compound. II. The proportions of the elements in a compound are always fixed. III. It is easy to separate the elements of a compound. IV. The elements/components of a compound do not retain their individual properties.
Chemistry
2 answers:
Ainat [17]3 years ago
6 0
1, 2, and 4 is the correct answer
marshall27 [118]3 years ago
5 0
All of them are properties of compounds except III.

for I, compounds are chemically combined together, so to separate them, we must use chemical methods like electrolysis or applying heat. These requires large amount of energy.

For II, they're always fixed. For example, in water (H2O), the ratio of hydrogen and oxygen is always 1:8 in mass. If there's some extra added, the substance becomes mixture instead of compounds.

For IV, after you chemically combined elements or compounds together, their properties are completely different. For example, iron can be attracted to magnets, but iron II sulphide does not.
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A 2.912 g sample of a compounds containing only C, H, and O was completely oxidized in a reaction that yielded 3.123 g of water
Taya2010 [7]

Answer:

Explanation:

18 gram of water contains 2 g of hydrogen

3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .

44 gram of carbon dioxide contains 12 g of carbon

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So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .

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Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )

= 0.175 : 0.029 : 0.347

= .175/ .029 : 1 : .347 / .029

= 6 : 1 : 12

So empirical formula = C₆H₁₂O

Let the molecular formula be (C_6H_{12}O)_n

molecular weight = n ( 6 x 12 + 12x 1 + 16)

= 100 n

Given 100 n = 100.1

n = 1

Molecular formula = C₆H₁₂O.

3 0
2 years ago
The rate constant for this second‑order reaction is 0.610 M − 1 ⋅ s − 1 0.610 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
Darya [45]

Answer: It takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

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a_0 = initial concentration = 0.860 M

a= concentration left after time t = 0.260 M

\frac{1}{0.260}=0.860\times t+\frac{1}{0.860}

t=3.120s

Thus it takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

8 0
3 years ago
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