Ask question

Ask question

All categories

2 years ago

9

A triangle has an area of 10 m². The height of the triangle is 5 m.

1 answer:

julsineya [31]2 years ago

5 0

Area=1/2 times bas time height
given that area=10
height=5
find base

10=1/2 times base times 5
times 2 both siddes
20=base times 5
divide oth sides by 5
4=base

the base is 4m

You might be interested in

I am going to buy exotic fruits. Dragonfruit costs $x-4$ dollars. Starfruit is five dollars less expensive than rambutan. Rambut

soldier1979 [14.2K]

We can represent the Rambutan as x-4+2x or 3x-4 because it costs 2x dollars more than the Dragonfruit.

We can represent the Starfruit as 3x-4-5 or 3x-9 because it costs 5 dollars less than the Rambutan

Therefore the overall equation would be:
(3x-4)+2(3x-9)+3(x-4) (distribute)
3x-4+6x-18+3x-12 (combine like terms)
12x-34

Hope this helps

8 0

3 years ago

Only 2/17 of the teachers were sciolists. If 3000 were not sciolists how many teachers were there in all

Juli2301 [7.4K]

$1-\frac{2}{17}=\frac{15}{17}\\
\frac{15}{17}--3000\\
1\ \ --x\\
x=3400$

5 0

2 years ago

Read 2 more answers

This is for imnotalexchill, imnotdanielchill, wolfgang21, iaintsusreally, and immagangstersike....

Annette [7]

Answer:

lol hey bestie!

Step-by-step explanation:

let's crush these boys!

4 0

2 years ago

Read 2 more answers

In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon

Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

$H_0: \mu=9.4\\\\H_a:\mu\neq9.4$ , since $H_0$ is two-tailed so , the test is a two tail test.

Since population standard deviation is unknown, so we use t-test.

Critical value (two-tailed) for significance level of 0.01= $t_{n-1,\alpha/2}=t_{49, 0.005}\pm2.609228$

For n =50 , $\overline{x}=8.6$ and s= 4.8

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

$t=\dfrac{8.6-9.4}{\dfrac{4.8}{\sqrt{50}}}\approx-1.18$

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.

We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

4 0

2 years ago

What is the rate of change of the function?<br><br>A. -3<br>B. -1/3<br>C. 1/3<br>D. 3

Rasek [7]

Answer:

c

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers