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Alika [10]
3 years ago
6

What is the volume of the cylinder below radius 8 height 3 in pi units Answer choices: A)96pi unit^3 B)192pi unit^3 C)225pi unit

^3 D)576pi unit^3
Mathematics
1 answer:
WARRIOR [948]3 years ago
7 0

Hey!

The formula for finding volume of a cylinder is: π · r² · h

r = 8 \\ r^{2} = 8 \times 8 = 64

h = 3

Now multiply

\pi \times 64 \times 3 = 192\pi

<em>Your answer is B)192π units³</em>

Good luck and hope this helps! :)

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Everythings in the pic!
yanalaym [24]

Answer:

  • D. 32 times; 5/4*40 = 32

Step-by-step explanation:

It is expected the spinner to land on Red 1/5 times.

<u>If the spinner is spun 40 times, then it should land on Red:</u>

  • 1/5*40 = 8 times

<u>And it should not land on red:</u>

  • (1 - 1/5)*40 = 4/5*40 = 32 times

Correct choice is D

3 0
2 years ago
Write an equation of the line in slope intercept form (0,5)(3,4)
hoa [83]
Find slope (y2-y1)/(x2-x1)
(4-5)/(3-0) = -1/3
Y = -1/3x + b
5 = -1/3(0) + b, b = 5
Equation: y = -1/3x + 5
5 0
3 years ago
Read 2 more answers
Need Help!
Contact [7]

Answer:

4) Alternate  Interior angles 5) Parallel lines property.

Step-by-step explanation:

The question is asking us to Complete the statements to prove that line AB ⩭ to line CD and line BC ⩭ to line AD.

In statement 4 .∠CAB is congruent to ∠ACD as AB is parallel to CD  and ∠BCA  is congruent to∠CAD as AD is parallel to BC  and these are Alternate interior angles to the parallel lines .

In statement 5.m∠CAB =∠ACD and ∠BCA = ∠CAD as by property of parallel lines Alternate interior angles are equal.

6 0
3 years ago
Read 2 more answers
You have just opened a new nightclub, Russ' Techno Pitstop, but are unsure of how high to set the cover charge (entrance fee). O
Neko [114]

Answer:

a)q(p)=-15p+ +300

b)R(p)=-15p²+300p

c)C(p)=-30p+1600

d.1)P(p)=-15p²+330p-1600

d.2)p=$11

Step-by-step explanation:

(a).Before getting started, we are going to consider  the cartesian plane, where x-axis corresponds to the cover charge and y-axis corresponds to number of guests per night . There, we will locate the following coordinates according to the previous information:

(9,165)  (10,150).

Remember that  the slope-intercept form of the  linear equation is y=mx+b where m is the slope and b  is te intercept.

The slope can be calculated  by the next formula:

m=\frac{y2-y1}{x2-x1}

In this case we will assign  (9,165) as the first coordinate and (10,150) as the second one. The order does not matter. At the end we get the same value for m.

Therefore:

m=\frac{150-165}{10-9} = -15

Now, we have the slope and two poitns. According to this, and taking into account that  point-slope form of the equation of a line is y-y1=m(x-x1),   find a linear demand equation.

Any of two coordintates can be selected. In this case we will select the second one.

y-150=-15(x-10)   equation 1

Solve equation 1 for y

y=-15x+150+150

y=-15x+300

Above we had defined x as cover charge (p) and y as number of guests (q). Thus, rewrite equation 1.

q(p)=-15p+ +300.  

it equation shows the number of guests per night as a function of the cover charge,

(b). The nightly revenue can be calculated multplying the price of the cover charge by  the number of guests. So, we just have to multiply the equation 1 by p.

p*q(p)=p*(-15p +300)

R(p)=-15p²+300p   equation 2

(c) To get the cost function of the nightclub  we just have to multiply the cost of the two non-alcoholic drinks   by the number of the guests ( equation 1) and add to it  nightly overheads.

C(p)=2*(-15p+300)+1000

C(p)= -30p+600+1000

C(p)=-30p+1600  equation 3

(d) In order to find the profit in terms of the cover charge we will  subtract nightly costs ( equation 3) from nightly revenue (equation 2)

P(p)=R(p)-C(p)

P(p)=-15p²+300p - (-30p+1600)

P(p)=-15p²+300p+30p-1600

P(p)=-15p²+330p-1600

To determine that  the entrance fee we should charge for a maximum profit we are going to use the first derivative test (y'(x)=0) in order to find an extremum point.

Compute the first derivative of P(p)

P'(p)=-30p+330=0

30p=330

p=330/30

p= $11

The entrance fee that we should charge for a maximum profit is p=$11 per guest.

5 0
3 years ago
timothyis re-arranging his marbles collection. he has 5 identical blue marbles, five green and 3 black. he can fit excactly 5 ma
Lerok [7]
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are  blue-green-black.

Now the rest of the collection consists of

                    4 blue
                    4 green
                    2 black

and there's space for 2 more marbles in the case.

So the question really asks:  "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"

-- Well, there are 10 marbles all together. 
So the first one chosen can be any one of the 10,
       and for each of those,
the second one can be any one of the remaining 9 .

Total number of ways to pick 2 out of the 10  =  (10 x 9)  =  90 ways.

-- BUT ... there are not nearly that many different combinations
to wind up with in the case.    

The first of the two picks can be any one of the 3 colors,
             and for each of those,
the second pick can also be any one of the 3 colors. 

So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
6 0
3 years ago
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