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klio [65]
3 years ago
5

What is the length of CD in this diagram ABC ~ EDC

Mathematics
2 answers:
aliina [53]3 years ago
6 0

We are given that:

ABC ~ EDC

So equating ratio of equal sides:

\frac{BC}{CD} = \frac{AC}{CE}

\frac{20-x}{x} = \frac{21}{7}

20-x =3x

20 =3x+x

20 =4x

dividing both sides by 4,

x=5

Answer is length of CD is x which is 5. Option C

LenKa [72]3 years ago
5 0

Answer:

C. 5

Step-by-step explanation:

Given the two triangles are similar, then its sides are proportional. In consequence the following relation must be satisfied:

BC/AC =  CD/CE

Replacing with the given values and solving for x, we get

(20 - x)/21 = x/7

(20 - x) = 21*x/7

20 - x = 3*x

20 = 3*x + x

20 = 4*x

20/4 = x

5 = x

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1/2 * 5 * 10/sqrt 3
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Hope this helps!
3 0
3 years ago
Nancy found that x=1 is one solution to the quadratic equation (x 2)2=a. what is the value of a? -9 -3 3 9
AlladinOne [14]

The value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.

<h3>What is the solution of equation?</h3>

The solution of the quadratic equation is the solution of the variable of the equation, for which the equation satisfies.

Nancy found that x=1 is one solution to the quadratic equation. The quadratic equation is,

(x +2)^2=a

For this equation, one solution is <em>x</em>=1. Put this value in the above equation to get the value of <em>a,</em>

(1 +2)^2=a\\(3)^2=a\\9=a\\a=9

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Learn more about the solution of the equation here;

brainly.com/question/21283540

5 0
2 years ago
Read 2 more answers
ABCD Is a rectangle that represents a park.
Andru [333]

Answer:

Shortest distance from A to C = 102.9005 m.

Step-by-step explanation:

It is given that, ABCD is a rectangular park.

The length of the park is 80 m.

The breadth of the park is 50 m.

The diameter of the circle = 15 m.

We have to calculate the shortest distance from A to C across the park.

The distance AC = \sqrt{50^{2}+80^{2} } = 94.339 m.

As one has to pass only through the lines shown, he cannot pass through the circle.

So, we have to subtract the diameter of 15 m from AC

=> 94.339 m - 15 m = 79.339 m.

One must pass through either half of the circumference of the circle.

Since, diameter of circle = 15 m, its radius(r) = \frac{15}{2} = 7.5 m.

The circumference of the circle = 2×π×r = 47.123 m.

Half of the circumference = \frac{47.123}{2} = 23.5615 m.

Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.

As we have to calculate the shortest distance from A to C, one cannot pass  from A to C either through B or D,

since the distance ABC or ADC = 50+80 = 130 m.

Therefore, shortest distance from A to C = 102.9005 m.

3 0
3 years ago
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Alex73 [517]

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Oksanka [162]

Answer:

D

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3 years ago
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