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OleMash [197]
4 years ago
8

Find the product. (8m2 – 1)(8m2 + 1)

Mathematics
2 answers:
Schach [20]4 years ago
8 0

Answer:

the answer is 64m^4 - 1

64m^4 + 8m^2 - 8m^2 - 1

Step-by-step explanation:

drek231 [11]4 years ago
5 0

Answer:

64m^4 – 1

Step-by-step explanation:

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How many times stronger is a magnitude 9.2 earthquake than a magnitude 6.4 earthquake? Round your answer to the nearest whole nu
Hatshy [7]

Answer:

i have tried but have no idea

help me too haha

Step-by-step explanation:

8 0
3 years ago
Which scenario involves the value of greatest magnitude?
Sonbull [250]

Answer:

D. A withdrawal of $30 from a bank account

Step-by-step explanation:

When it says magnitude it doesn't matter if it's a positive or negative number.

So it's just asking which number is the greatest which is 30.

I hope my explanation makes sense and helps you out.

5 0
3 years ago
sara making punch for her party her punch bowl holds 600 ounces for 80 servings of punch write and solve an equation to find how
nlexa [21]

There are 7.5 ounces in each serving

<em><u>Solution:</u></em>

Given that, Sara making punch for her party her punch bowl holds 600 ounces for 80 servings of punch

<em><u>To find: Ounces of punch in each serving</u></em>

From given,

Number of servings = 80

Ounces in bowl = 600 ounces

Then, Ounces of punch in each serving is found by dividing the ounces in bowl by number of servings

<em><u>The formula used is:</u></em>

\text{ Ounces of punch in each serving } = \frac{\text{Ounces in bowl}}{\text{Number of servings}}

<em><u>Substituting the values we get,</u></em>

\text{ Ounces of punch in each serving } = \frac{600}{80}\\\\\text{ Ounces of punch in each serving } = 7.5

Thus there are 7.5 ounces in each serving

5 0
3 years ago
Suppose that textbook weights are normally distributed. You measure 33 textbooks' weights, and find they have a mean weight of 7
AleksAgata [21]

Answer:

75-2.58\frac{13.3}{\sqrt{33}}=69.027    

75+2.58\frac{13.3}{\sqrt{33}}=80.793    

And the 95% confidence interval would be between (69.027;80.793)    

Step-by-step explanation:

Information given

\bar X=75 represent the sample mean

\mu population mean (variable of interest)

\sigma=13.3 represent the population standard deviation

n=33 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=33-1=32

The Confidence level is 0.99 or 99%, the significance would be \alpha=0.01 and \alpha/2 =0.005, the critical value for this case would be z_{\alpha/2}=2.58

And replacing we got:

75-2.58\frac{13.3}{\sqrt{33}}=69.027    

75+2.58\frac{13.3}{\sqrt{33}}=80.793    

And the 95% confidence interval would be between (69.027;80.793)    

6 0
3 years ago
Stephen can deliver 14 newspapers in 20 minutes. How many HOURS will it take him to deliver 131 newspaper
LiRa [457]

Answer:

approx. 3 hours

Step-by-step explanation:

14 newspapers in 20 minutes means he can deliver 42 newspapers an hour.

60/42 = 1.4285 newspapers per minute

131 x 1.4285 = 187.1335 minutes = 3.1188 hours

7 0
3 years ago
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