Answer:
<em>The work done by the car is 363 kJ</em>
Explanation:
Work : Work is said to be done when a Force moves an object through a certain distance. Work and Energy are interchangeable because they have the same unit. The unit of work is Joules (J).
Mathematically work done can be expressed as,
E = W = 1/2mv²
W = 1/2mv²................................ Equation 1
Where E = Energy, W = work done, m = mass of the car, v = velocity of the car
<em>Given: m=1500 kg, v=22 m/s</em>
<em>Substituting these values into equation 1</em>
<em>W = 1/2(1500)(22)²</em>
<em>W = 750 × 484</em>
<em>W = 363000 J</em>
<em>W = 363 kJ</em>
<em>Thus the work done by the car is 363 kJ</em>
Answer:
Final kinetic energy, 
Explanation:
It is given that,
Kinetic energy of toy car, 
Frictional force, F = 0.5 N
Distance, d = 6 m
We need to find the kinetic energy after this frictional force has acted on it. We know that frictional force is an opposing force. The work done by the toy car is given by :
W = -3 J
We know that the work done is equal to the change in kinetic energy. Let 
is the final kinetic energy.
So, the final kinetic energy is the toy car is 5 J. Hence, this is the required solution.
Answer:sofa
Explanation:the weight of the mass of that object can be heavy (er) than the rest
Answer:
V=483.63 m/s
Explanation:
Given that
mass ,m= 5.31 x 10⁻²⁶ kg
Kinetic energy KE= 6.21 x 10⁻²¹ J
As we know that the kinetic energy of the mass m with moving velocity V given as
Now by putting the values
V=483.63 m/s
Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.
Answer:
35 Joules
Explanation:
Applying
Input Energy(Q) = Useful energy output(U)+Wasted Energy(W)
Q = U+W.............................. Equation 1
Make U the subject of the equation
U = Q-W................... Equation 2
From the question,
Given: Q = 120 Joules, W = 85 Joules
Substitute these values into equation 2
U = 120-85
U = 35 Joules
