Answer:
13 m
Explanation:
It is given that :
I got a haircut sitting at a place having two parallel mirrors at a distance = 6.5 m apart
My head is at a distance of 2 m from the nearer mirror.
Now the light from the back of my head must go to (6.5 - 2) = 4.5 m to the back mirror.
Then it must go to 6.5 m to the front mirror and 2 m from the front mirror to my eyes.
So in order to see the back of my head, it will be = 6.5 + 2 + 4.5 = 13 m away.
Answer:
An average male lives 27,375 Days
The value of mass m = 0.506kg
Initial frequency = 0.78Hz
additional mass = 730 g = 0.73kg
New frequency = 0.65 Hz
F = 1/2π
0.78 = 1/2π 
additional mass,
0.65 = 1/2π 
1.44 = k/m / k/m+0.73
1.44 = m+0.73 / m
1.44m -m = 0.73
1.44m = 0.73
mass m = 0.506kg
a measurement used in physics to express the inertia, a quality that all matter has in common. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilograms is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one kilogramme times one square metre per second. The kilogramme is determined by precise measurements of Planck's constant, while the second and metre are already defined in terms of other physical constants.
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Answer:
(a) Tangential velocity will be 38.648 m/sec
(b) Acceleration will be 
Explanation:
We have given radius r = 11.2 m
Angular speed 
(a) We have to find the tangential velocity
We know that tangential velocity is given by

(b) We know that acceleration is given by

Explanation:
It is given that,
Current in wire 1, I₁ = 10 A
Current in wire 2, I₂ = 20 A
Distance between wires, d = 10 cm = 0.1 m
Force per unit length is given by :




So, the magnetic force acting per unit length of the wires
. Since, the current is in same direction. So, the force is attractive in nature.