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Bond [772]
2 years ago
12

The change in electric potential energy per unit charge is

Physics
2 answers:
Ahat [919]2 years ago
7 0

Answer:

d

Explanation:

zepelin [54]2 years ago
6 0

A) amperes

B) current.  

C) gravity.  

D) voltage.

correct. D) Voltage is the change in electric potential energy per unit charge. It is sometimes called the electric potential difference

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Write 4,007,500,000 in scientific notation.
Vika [28.1K]
The answer is 4.0075 x 10^9

7 0
2 years ago
What is the speed of a wave with a wavelength of 3 m and a frequency of .1Hz?
Yuri [45]
We know,
Speed = Frequency * Wavelength 
Speed = 3 * 0.1 m/s   [hertz = 1/sec.]
So, your final answer is 0.3 m/s

Hope this helps!!
6 0
3 years ago
Read 2 more answers
If 90 grams of gold has a volume of 5 cm3, calculate the density (include the units and show your work or you get no credit
ehidna [41]

Answer:

The density of gold is of 18 grams per cm3.

Explanation:

The mass density of a homogeneous material expresses how much mass of that material is present in a given volume. Since the density of an object is obtained by dividing its mass by its volume, to obtain the density of gold, its 90 grams of mass must be divided by its 5 cm3 volume, performing the following calculation:

90/5 = X

18 = X

Thus, the density of gold is 18 grams per cm3.

6 0
3 years ago
A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is
ivanzaharov [21]
<span>anwser will be 

F = ma

where 

F = force exerted on the bullet 
m = mass of the bullet = 5 gm (given) = 0.005 kg. 
a = acceleration of the bullet 

Substituting appropriately, 

F = 0.005a --- call this Equation 1 

Next working equation is 

Vf^2 - Vo^2 = 2as 

where 

Vf = velocity of the bullet as it leaves the muzzle = 326 m/sec (given) 
Vo = initial velocity of bullet = 0 
a = acceleration of bullet 
s = length of the rifle's barrel 

Substituting appropriately, 

326^2 - 0 = 2(a)(0.83) 

a = 64,022 m/sec^2 

the anwser will be
Substituting this into Equation 1, 

F = 0.005(64,022) 

F =320.11 Newtons 

Hope this helps. </span><span>
</span>
8 0
3 years ago
An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 115 m/s squared. What ar
Iteru [2.4K]
The direction of the electric field would be south. 

qE/m = 115 
<span>       E = 115*m/q </span>
<span>           = 115 * 9.1 * 10^(-31) / 1.67*10^(-19) </span>
<span>           = 762.87 * 10^(-12) </span>
<span>           = 6.27 x 10^-10 N/C
</span>
Hope this answers the question. Have a nice day. Feel free to ask more questions.
6 0
2 years ago
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