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Mars2501 [29]
3 years ago
8

The sun's apparent motion across the sky from East to West daily is due to the A) rotation of the sun. B) rotation of the earth.

C) orbit of the earth around the sun. D) orbit of the sun around the earth.
Physics
2 answers:
serious [3.7K]3 years ago
5 0
B)rotation of earth because we rotate around the sun so when your area faces away from the sun it looks like the sun is setting in your point of view.
svlad2 [7]3 years ago
4 0
<span>B) rotation of the earth.

The sun is relatively fixed. It is the rotation of the Earth that makes it appear as if the Sun is moving from East to West.
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Puck 1 (1 kg) travels with velocity 20 m/s to the right when it collides with puck 2 (1 kg) which is initially at rest. After th
Burka [1]

Answer:

Explanation:

Parameters given:

Mass of Puck 1, m = 1 kg

Mass of Puck 2, M = 1 kg

Initial velocity of Puck 1, u = 20 m/s

Initial velocity of Puck 2, U = 0 m/s

Final velocity of Puck 1, v = 5 m/s

Since we are told that momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum of the system = Total final momentum of the system

mu + MU = mv + MV

(1 * 20) + (1 * 0) = (1 * 5) + (1 * V)

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Answer: approximately 50%

Explanation:

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Is oxygen a reactant or product
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A toy rocket is launched straight up by using a spring. The rocket is initially pressed down on the spring so that the spring is
tigry1 [53]

Answer:

6.86 meters

Explanation:

Let the compression of the string be represented by x, and the height of projection of the toy rocket be represented by h.

So that;

x = 9 cm = 0.09 m

In its rest position (i.e before the launch), the spring has a stored potential energy which is given as;

PE = \frac{1}{2} Kx^{2}

    = \frac{1}{2} x 830 x (0.09)^{2}

    = 415 x 0.0081

    = 3.3615

The potential energy in the string = 3.36 Joules

Also,

PE = mgh

where: m is the mass, g is the gravitational force and h the height.

m = 50 g = 0.05 kg, g = 9.8 ms^{-2}

Thus,

PE = 0.05 x 9.8 x h

3.3615 = 0.05 x 9.8 x h

3.3615 = 0.49h

⇒ h = \frac{3.3615}{0.49}

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The height of the toy rocket would be 6.86 meters.

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