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Ad libitum [116K]
3 years ago
9

Sum of three like fractions is 18/11. the first 2 fractions are 1/11 and 9/11. find the third fraction.

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

\frac{8}{11}

Step-by-step explanation:

Since the fractions are like, their denominators are 11, then

consider the values that sum to give 18 , that is

1 + 9 + ? = 18

10 + ? = 18 ( subtract 10 from both sides )

? = 8

Then the third fraction is \frac{8}{11}

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The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
Item 4
Simora [160]

Answer:

270 s

Step-by-step explanation:

4 minutes = 240s

add the other 30s

boom

5 0
3 years ago
Read 2 more answers
A number line contains points Q, R, S, and T. Point Q is on the coordinate 24, R is on the coordinate 28, S is on the coordinate
const2013 [10]

|\Omega|=QT=42-24=18\\ |A|=ST=42-29=13\\\\ P(A)=\dfrac{13}{18}\approx72.2\%\Rightarrow \text{D}

7 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through the points (0, -3) and (-4,1).
kozerog [31]

The formula for slope is \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

In this case:

y_{2} = 1\\ y_{1} }= -3\\x_{2} = -4\\x_{1} = 0

so...

\frac{1 - (-3)}{-4 - 0}

\frac{4}{-4}

-1 <<<The slope

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
Read 2 more answers
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Artyom0805 [142]

Answer:

iugyvhjbnkijogyutfvbh

Step-by-step explanation:

:D

8 0
3 years ago
Read 2 more answers
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