Answer:
51 cm^2
Step-by-step explanation:
To find the area excluding the shaded triangle, first find the area of the whole figure:
12 x 6 = 72cm^2
Now, find the area of the triangle:
(7 x 6) / 2
42/2
21cm^2
Lastly, subtract the shaded area from the whole:
72 - 21 = 51 cm^2
In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
Answer:
No solutions
Step-by-step explanation:
2(x+1)=2x+5
Expand the parentheses:
2x+2=2x+5
Subtract 2x from both sides:
2=5
Since this is not true, this equation has no solutions. Hope this helps!
Step-by-step explanation:
such a scale factor applies to all sides and lines.
we see that DE is 12 units, and AB is 4 units.
so,
12×f = 4
f = 4/12 = 1/3 is the scale factor
control : check the other side
FE = 6 units
6 × 1/3 = 2
so, the corresponding side in the small triangle must be 2 units long.
and indeed, CB is 2 units long. all correct.
