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steposvetlana [31]
4 years ago
11

A stone falls freely from rest for 18 s. The acceleration due to gravity is 9.8 m/s 2. What was the stone’s displacement after t

hat time? ans in m
Physics
1 answer:
4vir4ik [10]4 years ago
4 0

-- At the end of 18sec, the stone's velocity is (9.8m/s² x 18s) = 176.4m/s downward.

-- Starting at 0 m/s and ending at 176.4m/s, its average velocity is 88.2m/s downward.

-- Falling for 18s at an average speed of 88.2m/s, it falls (88.2m/s x 18s) = 1,587.6 m .

-- Its displacement is <em>1,587.6 meters downward.</em>

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From the question we are told that

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