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2 years ago

In the Boyle’s law experiment, what was used to increase the pressure on the air (gas)?

Physics

1 answer:

MA_775_DIABLO [31]2 years ago

8 0

Answer:

Volume.

Explanation:

Boyle’s law experiment :

This is also known as Mariotte's law or in the other words it is also known as Boyle–Mariotte law.

This law tell us about the variation of gas pressure when the volume of the gas changes at the constant temperature.According to this law the abslute pressure is inversely proportional to the volume .

We can say that

$P\alpha \dfrac{1}{V}$

Where P=Pressure

V=Volume

PV = K

K=Constant

When volume decrease then the pressure of the gas will increase.

That is why the answer is "Volume".

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A car and a truck are moving next to each other on the highway. The truck has a mass of 910 kg and the car’s mass is 227 kg. IF

eimsori [14]

Answer:

<h2>the car must move with the speed</h2><h2> $v = 72.16 m/s$ </h2>

Explanation:

As we know that the momentum of the car and truck is same

so as per the formula of momentum we have

$P = mv$

so we have

$m_1v_1 = m_2v_2$

so we will have

$910 \times 18 = 227 v$

$v = 72.16 m/s$

So the car must move with the speed

$v = 72.16 m/s$

3 0

2 years ago

A student connects a 1 hp motor to a bicycle. How much time will it take for the bicycle to accelerate from rest to a speed of 5

bija089 [108]

Answer:

t=2s

Explanation:

The definition of power is:

$P=\frac{W}{t}$

And the work-energy theorem states that:

$W=\Delta K$

Since the movement starts from rest, we have that:

$\Delta K=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}=\frac{mv_f^2}{2}$

And putting all together:

$P=\frac{mv_f^2}{2t}$

Since we want the time taken:

$t=\frac{mv_f^2}{2P}$

Which for our values is:

$t=\frac{(120kg)(5m/s)^2}{2(746W)}=2s$

7 0

3 years ago

Read 2 more answers

The downsprue leading into the runner of a certain mold has a length of 175 mm. The cross-sectional area at the base of the spru

adoni [48]

Answer:

(a) Velocity at bottom is 1.85 m/s

(b) Volume flow rate is 7.4 x 10⁻⁴ m³/s.

Explanation:

(a)

Applying Bernoulli's Equation on both ends of the down sprue, with the assumptions that every point is at atmospheric pressure and the liquid metal at the pouring basin is at zero velocity. The equation then becomes:

V = √2gh

where,

V = velocity at bottom of down sprue

h = height of down sprue = 175 mm = 0.175 m

V = √2(9.8 m/s²)(0.175 m)

<u></u>

(b)

The volume flow rate is given as:

Volume Flow Rate = (V)(A)

where,

V = velocity at bottom = 1.85 m/s

A = Area of bottom = 400 mm² = 0.0004 m²

Therefore,

Volume Flow Rate = (1.85 m/s)(0.0004 m²)

<u>Volume Flow Rate = 7.4 x 10⁻⁴ m³/s = 740 cm³/s</u>

(c)

The time required to fill the cavity is given as:

Volume Flow Rate = V/t

where,

V = Volume of mold Cavity = 0.001 m³

t = time required to fill the cavity = ?

Therefore,

t = V/Volume Flow Rate

t = 0.001 m³/7.4 x 10⁻⁴ m³/s

<u></u>

5 0

3 years ago

49. \ A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner

faust18 [17]

Answer:

$\frac{L_1}{L_2} = \sqrt{(n^2 - 1)}$

Explanation:

For this interesting problem, we use the definition of centripetal acceleration

a = v² / r

angular and linear velocity are related

v = w r

we substitute

a = w² r

the rectangular body rotates at an angular velocity w

We locate the points, unfortunately the diagram is not shown. In this case we have the axis of rotation in a corner, called O, in one of the adjacent corners we call it A and the opposite corner A

the distance OB = L₂

the distance AB = L₁

the sides of the rectangle

It is indicated that the acceleration in in A and B are related

$a_A = n \ a_B$

we substitute the value of the acceleration

w² r_A = n r_B

the distance from the each corner is

r_B = L₂

r_A = $\sqrt{L_1^2 + L_2^2}$

we substitute

\sqrt{L_1^2 + L_2^2} = n L₂

L₁² + L₂² = n² L₂²

L₁² = (n²-1) L₂²

4 0

3 years ago

How does a decrease in thermal energy affect the particle motion in each state of matter

Valentin [98]

The thermal energy is proportional to the movement of the particles in every state.

Decreasing the thermal energy will decrease the movement.

3 0

3 years ago