Answer:
I=1A
Explanation:
In parallel combination voltage is same
In R1
V=IR
V=2×4
V=8V
In R2
V=IR
I=V/R
I=8/8
I=1A
Answer:
a) 60 V
b) 125 V
c) 125 V
Explanation:
<u>Given</u>
We are given the total electric charge q = 6.75 nC = 6.75x 10^-9 C distributed uniformly over the surface of a metal sphere with a radius of R = 20.0 cm = 0.020 m.
<u>Required </u>
We are asked to calculate the potential at the distances
(a) r = 10.0 cm
(b) r = 20.0 cm
(c) r = 40.0 cm
<u>Solution</u>
(a) Here, the distance r > R so, we can get the potential outside the sphere (r > R) where the potential is given by
V = q/4
∈_o (1)
r is the distance where the potential is measured and the term 1/4
∈_o equals 9.0 x 10^9 Nm^2/C^2. Now we can plug our values for q and r into equation (1) to get the potential V where r = 0.10 m
V= 1*q/4
∈_o*r
=60 V
(b) Here the distance r is the same for the radius R, so we can get the potential inside the sphere (r = R) where the potential is given by
V = 1*q/4
∈_o*R (2)
Now we can plug our values for q and R into equation (2) to get the potential V where R = 0.20 m
V = 1*q/4
∈_o*R
= 125 V
(c) Inside the sphere the electric field is zero therefore, no work is done on a test charge that moves from any point to any other point inside the sphere. Thus the potential is the same at every point inside the sphere and is equal to the potential on the surface. and it will be the same as in part (b)
V= 125 V
Answer:
d) -4.0
Explanation:
The magnification of a lens is given by

where
M is the magnification
q is the distance of the image from the lens
p is the distance of the object from the lens
In this problem, we have
p = 50 cm is the distance of the object from the lens
q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct
Also, q is positive since the image is real
So, the magnification is

The pressure at the bottom of the tank is given by:
P = ρgh
P = pressure, ρ = fluid density, g = gravitational acceleration, h = depth
Given values:
ρ = 820kg/m³, g = 9.8m/s², h = 4.5m
Plug in and solve for P:
P = 820(9.8)(4.5)
P = 36000Pa
Answer:
The angle is 
Explanation:
From the question we are told that
The mass is 
The radius is 
The speed is 
According to the law of energy conservation
The potential energy of the mass at the top is equal to the kinetic energy at the bottom i.e

=> 
Here h is the vertical distance traveled by the mass which is also mathematically represented as

So
![\theta = sin ^{-1} [ \frac{1}{2* g* r } * v^2]](https://tex.z-dn.net/?f=%5Ctheta%20%20%20%3D%20sin%20%5E%7B-1%7D%20%5B%20%5Cfrac%7B1%7D%7B2%2A%20g%2A%20r%20%7D%20%2A%20%20v%5E2%5D)
substituting values
![\theta = sin ^{-1} [ \frac{1}{2* 9.8* 1.1 } * (3.57)^2]](https://tex.z-dn.net/?f=%5Ctheta%20%20%20%3D%20sin%20%5E%7B-1%7D%20%5B%20%5Cfrac%7B1%7D%7B2%2A%209.8%2A%201.1%20%7D%20%2A%20%20%283.57%29%5E2%5D)
