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3 years ago

A star may form a black hole once it cannot ?

1 answer:

4 0

A star may form a black hole once is true. After the marked supernova explosion, the star shrinks because it sheds away the gaseous layers of the star. And especially if the star is large, it will form into a black hole.

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A car traveling at 30 m/s runs out of gas while traveling up a 10 slope. how far up the hill what coast before starting to roll

kaheart [24]

Answer:

264.7 m

Explanation:

The net force felt by the car travelling along the slope is equal to the component of the weight parallel to the slope, so:

$F=-mg sin \theta$

where

m is the mass of the car

g = 9.8 m/s^2 is the acceleration of gravity

$\theta=10^{\circ}$

and the negative sign is due to the fact the force is opposite direction to the motion of the car

The acceleration of the car is therefore:

$a=\frac{F}{m}=-gsin \theta=-9.8 sin 10^{\circ}=-1.7 m/s^2$

Now we can find how far the car went up the hill by using the equation:

$v^2-u^2 = 2ad$

where

v = 0 is the final velocity of the car

u = 30 m/s is the initial velocity

g = -1.7 m/s^2 is the acceleration

d is the distance covered

Solving for d,

$d=\frac{v^2-u^2}{2a}=\frac{0-30^2}{2(-1.7)}=264.7 m$

3 0

4 years ago

A 77.3 g mass is attached to a horizontal spring with a spring constant of 12.5 N/m and released from rest with an amplitude of

DENIUS [597]

Answer:

speed of the mass is 3.546106 m / s

Explanation:

given data

mass = 77.3 g = 77.3 × $10^{-3}$ kg

spring constant k = 12.5 N/m

amplitude A = 38.9 cm = 38.9 × $10^{-2}$ m

to find out

the speed of the mass

solution

we will apply here conservation energy that is

K.E + P.E = Total energy ..................1

so that Total energy = K.E max = P.E max

we know amplitude so we find out first P.E max that is

PE max = K.E + P.E

(1/2)kA² = (1/2)mv² + (1/2)kx²

kA^² = mv²+ kx²

so here v² will be

v² = k(A² - x²) / m

v = √[(k/m)×(A² - x²)] ............2

here x = (1/2)A so from from 2 equation

v = √[(k/m)×(A² - (A/2)²)]

v = √[(k/m)×(3/4×A²)]

now put all value

v = √[(12.5/ 77.3 × $10^{-3}$ )×(3/4×(38.9 × $10^{-2}$ )²)]

v = 3.546106 m / s

speed of the mass is 3.546106 m / s

6 0

3 years ago

What happens when a candle burns?

slega [8]

Answer:

oxygen is used up is the answer

Explanation:

These vaporized molecules are drawn up into the flame, where they react with oxygen from the air to create heat, light, water vapor (H2O) and carbon dioxide (CO2).

5 0

3 years ago

All ball is thrown up with a vertical velocity of 54 m/s and a horizontal velocity of 39 m/s. Calculate how many seconds it will

VikaD [51]

5.5 s

Explanation:

The time it takes for the ball to reach its maximum height can be calculated using

$v_y = v_{0y} - gt \Rightarrow t = \dfrac{v_{0y}}{g}$