15. 
Add "g" on both sides
Multiply 5 on both sides to get x by itself
x = 5(a + g)
x = 5a + 5g
18. a = 3n + 1
Subtract 1 on both sides
a - 1 = 3n
Divide 3 on both sides to get n by itself
= n
21. M = T - R
Add "R" on both sides to get "T" by itself
M + R = T
24. 5p + 9c = p
Subtract "5p" on both sides
9c = p - 5p
9c = -4p
Divide 9 on both sides to get "c" by itself
c = 
or c = 
27. 4y + 3x = 5
Subtract "4y" on both sides
3x = 5 - 4y
Divide 3 on both sides to get "x" by itself
x = 
x = 
The correct option is the second one y<=1/2x+3
Answer:
23 males and 12 females
Step-by-step explanation:
x = # of females
y = # of males
x + y = 35
x + x + 11 = 35
2x + 11 =35 (SUBTRACT 11 FROM BOTH SIDES)
2x = 24 (DIVIDE BOTH SIDES BY 2)
x = 12 females
x + y =35
12 + y = 35 (SUBTRACT 12 FROM BOTH SIDES)
y = 23 males
23 males + 12 females = 35 students
Answer:
There are 10 counters in the bag and you want the 4
As their is only one for the probability is
1/10
There are now 9 counters left in the bag.
You only want the even ones , which are 2 6 8 and 10 ( four has been taken out)
There are only four even counters in the bag of nine counters so the probability is
4/9
As you want both of these to occur, you need to multiply them
1/10 x 4/9 = 49/90
Step-by-step explanation:
