Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Answer:
<h3>
a. 3x+15</h3><h3>
b. 4x-16</h3><h3>
c. 10x+2</h3><h3>
D. 7x-63y</h3>
solution,
Hope this helps..
Good luck on your assignment..
Answer:
x = 4
x = -4
Step-by-step explanation:
bro i dont know but i hope this help a little, sorry
We can start by figuring out the axis of symmetry.
y = x² + 12x = x (x + 12)
So roots are x = -12 or 0
Therefore axis of symmetry is x = (-12 + 0) / 2 = -6
We got x-coordinate of vertex. Now plug in x=-6 to solve for y.
y = (-6)² + 12(-6) = 36 - 72 = -36
Therefore vertex is (-6, -36).
Answer:
b/a
Step-by-step explanation:
Given,(b^-2)/a*(b^-3)
or,(b^-2+3)/a
or,b/a
