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Ierofanga [76]
3 years ago
14

I will give brainliest to first CORRECT answer.

Mathematics
2 answers:
astraxan [27]3 years ago
7 0

Answer:

C. 576 ft.

Step-by-step explanation:

If the garden has a perimeter of 72feet and the lengths of each of the sides are lengthened by a factor of 8.

Perimeter of the enlarged garden = perimeter before enlargement x enlargement factor

That’s 72 x 8

576feet

Olenka [21]3 years ago
7 0

Answer:

C. 576 ft. i answered this just to give the other person brainliest because im doing the same question at the moment so i figured itll make up for helping me :)

Step-by-step explanation:

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Answer:

x^4 -x^3 -4x^2-3

Step-by-step explanation:

f(x)=x^4−x^2+9  

g(x)=x^3+3x^2+12

(f−g)(x)= x^4−x^2+9 - (x^3+3x^2+12)

 Distribute the minus sign

(f−g)(x)= x^4−x^2+9 - x^3-3x^2-12

I like to line them up vertically

x^4        −x^2+9

    - x^3 -3x^2-12

---------------------------

x^4 -x^3 -4x^2-3

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AB. CD. EF are three chords of a circle, P and Q are two points inside the circle such that AB and CD meet at P, and AB and EF m
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Step-by-step explanation:

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Scientific notation 1.080000000​
denis-greek [22]

Step-by-step explanation:

u can answer 1.08 or 1.08 × 10^0

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Tammy is 8 years older than mike. jane is twice as old as mike. the sum of there ages is 52
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Step-by-step explanation:

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Find a set of vectors {u⃗ ,v⃗ }{u→,v→} in r4r4 that spans the solution set of the equations {w−x+2y+4z5w+2x−y+3z==0,0. {w−x+2y+4
rusak2 [61]
Given

w-x+2y+4z=0 \\ 5w+2x-y+3z=0

We can rewrite it in matrix form as:

\left[\begin{array}{cccc}1&-1&2&4\\5&2&-1&3\\0&0&0&0\\0&0&0&0\end{array}\right]   \left[\begin{array}{c}w\\x\\y\\z\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right] \\  \\ \left[\begin{array}{cccc}1&-1&2&4\\5&2&-1&3\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \ -5R_1+R_2\rightarrow R_2
\left[\begin{array}{cccc}1&-1&2&4\\0&7&-11&-17\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \  \frac{1}{7} R_2\rightarrow R_2 \\  \\ \left[\begin{array}{cccc}1&-1&2&4\\0&1&-\frac{11}{7}&-\frac{17}{7}\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \ R_1+R_2\rightarrow R_1
\\  \\ \left[\begin{array}{cccc}1&0&\frac{3}{7}&\frac{11}{7}\\0&1&-\frac{11}{7}&-\frac{17}{7}\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right] \\  \\ \Rightarrow w= -\frac{3}{7} y- \frac{11}{7} z \\ x=\frac{11}{7} y+ \frac{17}{7} z \\ y=free \\ z=free \\  \\ =y\left\ \textless \ -\frac{3}{7},\frac{11}{7}1,0\right\ \textgreater \ +z\left\ \textless \ - \frac{11}{7},\frac{17}{7},0,1\right\ \textgreater \

Thus, the solution set is a span of \{\left\ \textless \ -\frac{3}{7},\frac{11}{7}1,0\right\ \textgreater \ ,\left\ \textless \ - \frac{11}{7},\frac{17}{7},0,1\right\ \textgreater \ \}
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