A=length x height. First we want to know the area of the original sheet of paper. 8.5 x 11= 93.5 inches squared. Then we take two squares with side length 2 inches. The area of each of these squares is 2 x 2, or 4 inches. Since there are two, the total area we take away is 8 inches. We subtract 8 inches from 93.5 since we took it away, and the final area of the paper is 85.5 inches^{2}
Hope this helped!
Answer:
z = -ln│5eᵗ + C│
Step-by-step explanation:
dz/dt + 5eᵗ⁺ᶻ = 0
dz/dt = -5eᵗ⁺ᶻ
dz/dt = -5eᵗeᶻ
-e⁻ᶻ dz = 5eᵗ dt
e⁻ᶻ = 5eᵗ + C
-z = ln│5eᵗ + C│
z = -ln│5eᵗ + C│
I'm not sure if you use "x" as your variable, so:
# + 5 = 3 or x + 5 = 3
Answer:
Simplify the equation
Step-by-step explanation:
4x + 1 + x + -4
= 4x + x + 1 - 4
= 5x + -3
= 5x - 3
Hope this helps
First term (a) = -15
common difference(d)= -9-(-15)
= -9+15=6
So,
12th term(a12)= a +(n-1)d
= -15+(12-1)×6
= -15 + 11×6
= -15+66
= 51
