U r going to subtract 3 from each side of the equation....leaving you with :
x^2 + 2x = -3
Hello from MrBillDoesMath!
Answer:
Choice C, sqrt(3-x)
Discussion:
Have no fear, MBill is here!
The quotient is
sqrt (9-x^2) / sqrt( 3+x) = => as sqrt(a)/sqrt(b) = sqrt(a/b), b <> 0
sqrt ( (9-x^2)/( 3+x) ) = => as 9 - x^2 = (3-x) * (3+x)
sqrt ( (3-x)(3+x) /(3+x) ) = => cancel (3+x) from num. and denom.
sqrt( 3-x)
This is Choice C
Note the domain restriction -3 < x < = 3 guarantees that division by zero can't happen.
Thank you,
MrB
Do you want the answer for question 1!? It's already done! It says Given right there, that's an example answer :)
Answer:
They subtracted 2x from both sides.
Step-by-step explanation:
They removed 2x from each side because in order to find x it will have to be removed on one side. Since 2x - 2x = 0 it is 2x is out of the equation for the right side and on the left side -2x -(-4x) = -6x which means that there is one x variable left in the equation thus making it solvable.
