HELP GEOMTRY TEST !!!

The mean of a set of data is the ...

Rashid [163]

Answer: average

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

4.

sveticcg [70]

(a)The domain of the function is, $\rm x \geq -c^2 \ x\neq0$

(b)The given function is discontinuous at x=0.

<h3>What is the domain and range of a function?</h3>

Domain is the set of values for which the given function is defined. Range is the set of all values which the given function can output.

The standard function is;

$\rm f(x)= \frac{\sqrt{x+c^2-c} }{x} , c > 0$

The domain of the given function is found as;

$\rm x+c^2 \geq 0 \ x\neq 0 \\\\ x\geq-c^2 \ x\neq 0$

The domain of the function is,

$\rm x \geq -c^2 \ x\neq0$

To find the function is continuous or not, we have to find the continuity;

$\rm f(x) = \frac{\sqrt{ x+c^2-c}}{x} ,c > 0$

At x= 0 the function is undefined. So that the function is discontinuous at x=0.

Hence, The domain of the function is, $\rm x \geq -c^2 \ x\neq0$ and the function is discontinuous at x=0.

To learn more about domain, refer to the link:

brainly.com/question/20073127

#SPJ1

7 0

3 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

Triangle ABC is congruent to triangle DFE. Find x<br><br> 6<br><br> 12<br><br> 8<br><br> 4

RoseWind [281]

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3 0

4 years ago

1.What is the core characteristic that defines a zero-based budget?

lakkis [162]

Answer:

1. You account for every dollar you make to where your budget shows you have $0

2. She will have $125 leftover to budget out as she sees fit

3. If she does not account for it she may over spend or think she has extra money

4. I would put it in savings

5. No this is not what it means. This means that your paycheck will be able to cover your expenses.

6. You should put extra money in savings. You never know what will occur and savings can always help.

Step-by-step explanation:

7 0

3 years ago