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3 years ago

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What is the equation of the line that passes through the point (-2,7) and is perpendicular to the line 2 - 4y = 24?

1 answer:

alisha [4.7K]3 years ago

5 0

Answer:

u usin bodmas ok I hope bodmas help u do we are solve this step by step ok

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Answer this and ill give brainliest

nekit [7.7K]

Answer:

-4.65< -4 and 2/5

Step-by-step explanation:

To solve, this we can convert the fraction -4 and 2/5 into a decimal so that the values can be more easily compared. When we do this, we get the result that -4 and 2/5 equals -4.4. Now we can clearly see which value is greater because they are written in the same form:

-4.65<-4.4

-4.65<-4 2/5

6 0

2 years ago

Read 2 more answers

Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2

evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

$\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}$

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

$\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}$

Step # 1 : Swap the first and second matrix rows,

$\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}$

Step # 2 : Cancel leading coefficient in row 2 through $R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1$ ,

$\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}$

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

$\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}$

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0

3 years ago

I need help with both of these questions please

tankabanditka [31]

Answer:

$\frac{22}{30} = \frac{11}{15}$

and

$\frac{176}{7} = 25 \frac{1}{7}$

Step-by-step explanation:

First make all the fractions into improper fractions

$1\frac{5}{6} = \frac{11}{6} \\\\2\frac{1}{2} = \frac{5}{2} \\\\3\frac{1}{7} = \frac{22}{7}$

After doing that put them back into the problems

Problem 1)

$1\frac{5}{6}$ ÷ $2\frac{1}{2}$ , plug in the improper fractions

$\frac{11}{6}$ ÷ $\frac{5}{2}$

to divide, you need to flip the second fraction and multiply

$\frac{11}{6}$ · $\frac{2}{5}$ = $\frac{22}{30}$

then reduce

$\frac{22}{30} = \frac{11}{15}$

Problem 2)

$3\frac{1}{7}$ ÷ $\frac{1}{8}\\$

Plug in improper fraction

$\frac{22}{7}$ ÷ $\frac{1}{8}\\$

Then flip second fraction and multiply

$\frac{22}{7}$ · $\frac{8}{1}$

Multiply

$\frac{176}{7}$

Reduce, or make it a mixed number

$\frac{176}{7} = 25 \frac{1}{7}$

3 0

3 years ago

Several ordered pairs from a continuous exponential function are shown in the table. what are the domain and range of function?

son4ous [18]

the answer is b......

5 0

3 years ago

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What is the median of the data set?

Artist 52 [7]

Answer:

11.7

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers