In which number is the digit 7 ten time larger than it is in the number 794

100 POINTS+BRAINLIEST: 8TH GRADE MATH PT 3- Write equations by simplifying polynomials Tyyy

d1i1m1o1n [39]

Answer:

d. 3x + 6 = 26

Step-by-step explanation:

Definitions

Integer: a whole number that can be positive, negative or zero.
e.g. ..., -3, -2, -1, 0, 1, 2, 3, ...
Even number: an integer that is exactly divisible by two. For example, 2, 4, 6, 8 are all positive even numbers.
Consecutive: following one after the other in order.

The sum of three consecutive even integers

Let x be the first even integer.

As there is a difference of 2 between consecutive even integers, the next even integer after x will be (x + 2).

Therefore, the next even integer after (x + 2) will be (x + 2) + 2 = (x + 4).

So "the sum of three consecutive even integers is twenty-six" is:

x + (x + 2) + (x + 4) = 26

To solve

⇒ x + (x + 2) + (x + 4) = 26

⇒ x + x + 2 + x + 4 = 26

⇒ 3x + 6 = 26

(Please note that there are no three consecutive even integers that sum to 26, so the problem cannot be solved).

7 0

1 year ago

Read 2 more answers

Grade 10 Math. Solve for y. Will mark right answer brainliest :)

Dima020 [189]

Answer:

y=5, y= $\frac{38}{11}$

Step-by-step explanation:

Hi there!

We are given the equation

$\frac{y+2}{y-3}$ + $\frac{y-1}{y-4}$ = $\frac{15}{2}$ and we need to solve for y

first, we need to find the domain, which is which is the set of values that y CANNOT be, as the denominator of the fractions cannot be 0

which means that y-3≠0, or y≠3, and y-4≠0, or y≠4

$\frac{y+2}{y-3}$ and $\frac{y-1}{y-4}$ are algebraic fractions, meaning that they are fractions (notice the fraction bar), but BOTH the numerator and denominator have algebraic expressions

Nonetheless, they are still fractions, and we need to add them.

To add fractions, we need to find a common denominator

One of the easiest ways to find a common denominator is to multiply the denominators of the fractions together

Let's do that here;

on $\frac{y+2}{y-3}$ , multiply the numerator and denominator by y-4

$\frac{(y+2)(y-4)}{(y-3)(y-4)}$ ; simplify by multiplying the binomials together using FOIL to get:

$\frac{y^{2}-2y-8}{y^{2}-7y+12}$

Now on $\frac{y-1}{y-4}$ , multiply the numerator and denominator by y-3

$\frac{(y-1)(y-3)}{(y-4)(y-3)}$ ; simplify by multiplying the binomials together using FOIL to get:

$\frac{y^{2}-4y+3}{y^{2}-7y+12}$

now add $\frac{y^{2}-2y-8}{y^{2}-7y+12}$ and $\frac{y^{2}-4y+3}{y^{2}-7y+12}$ together

Remember: since they have the same denominator, we add the numerators together

$\frac{y^{2}-2y-8+y^{2}-4y+3}{y^{2}-7y+12}$

simplify by combining like terms

the result is:

$\frac{2y^{2}-6y-5}{y^{2}-7y+12}$

remember, that's set equal to $\frac{15}{2}$

here is our equation now:

$\frac{2y^{2}-6y-5}{y^{2}-7y+12}$ = $\frac{15}{2}$

it is a proportion, so you may cross multiply

2(2y²-6y-5)=15(y²-7y+12)

do the distributive property

4y²-12y-10=15y²-105y+180

subtract 4y² from both sides

-12y-10=11y²-105y+180

add 12 y to both sides

-10=11y²-93y+180

add 10 to both sides

11y²-93y+190=0

now we have a quadratic equation

Let's solve this using the quadratic formula

Recall that the quadratic formula is y=(-b±√(b²-4ac))/2a, where a, b, and c are the coefficients of the numbers in a quadratic equation

in this case,

a=11

b=-93

c=190

substitute into the formula

y=(93±√(8649-4(11*190))/2*11

simplify the part under the radical

y=(93±√289)/22

take the square root of 289

y=(93±17)/22

split into 2 separate equations:

y= $\frac{93+17}{22}$

y= $\frac{110}{22}$

y=5

and:

y= $\frac{93-17}{22}$

y= $\frac{76}{22}$

y= $\frac{38}{11}$

Both numbers work in this case (remember: the domain is y≠3, y≠4)

So the answer is:

y=5, y= $\frac{38}{11}$

Hope this helps! :)

5 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

ikadub [295]

Answer: 4095

Step-by-step explanation:

He sold 1 car on the first day so the first term (a) is 1. The amount doubles each month so the ratio (r) is 2.

Input those values into the Sum formula:

$S_n=\dfrac{a(1-r^n)}{1-r}\\\\S_{12}=\dfrac{1(1-2^{12})}{1-2}\\\\.\quad=\dfrac{1-4096}{-1}\\\\.\quad=\dfrac{-4095}{-1}\\\\.\quad=4095$

7 0

3 years ago

The table shows how the number of pepperoni

velikii [3]

I’ll try, hopefully I get it right

6 0

2 years ago

HELP DOES ANYONE KNOW “?”

lakkis [162]

Answer:

hope it helps...any queries comment me!!!

4 0

2 years ago