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2 years ago

Question 5(Multiple Choice Worth 4 points)

Mathematics

1 answer:

Aleks [24]2 years ago

7 0

Hello!

The number 49 is similar to other numbers like 25, 81, 4, or 64. All these numbers are perfect squares. Perfect squares are numbers multiplied by itself. Here is a list of commonly used perfect squares.

1 × 1 = 1
2 × 2 = 4
3 × 3 = 9
4 × 4 = 16
5 × 5 = 25
6 × 6 = 36
7 × 7 = 49
8 × 8 = 64
9 × 9 = 81
10 × 10 = 100
11 × 11 = 121
12 × 12 = 144

From the list above, the square root of 49 is 7, but the question asks for the negative square root of 49, which is written as: -√49.

To simplify this expression, first, simplify the radical, and then multiply the product by negative one.

7 × -1 = -7

Therefore, the negative square root of 49 is choice C, - 7.

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$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

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