All categories

3 years ago

What does the subscript 2 indicate in the formula o2?

1 answer:

6 0

The subscript 2 in the formula o2 indicates that there are 2 atoms of the element oxygen, represented by the symbol "O." The subscript to the right of the symbol tells how many atoms are present of that element.

You might be interested in

What is the maximum mass of b4c that can be formed from 2.00 moles of boron(iii) oxide?

anzhelika [568]

The maximum mass of B₄C that can be formed from 2.00 moles of boron (III) oxide is 55.25 grams.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the relative amount of moles of reactants and products present in the given chemical reaction.

Given chemical reaction is:

2B₂O₃ + 7C → B₄C + 6CO

From the stoichiometry of the reaction, it is clear that:

2 moles of B₂O₃ = produces 1 mole of B₄C

Now mass of B₄C will be calculated by using the below equation:

W = (n)(M), where

n = moles = 1 mole
M = molar mass = 55.25 g/mole

W = (1)(55.25) = 55.25 g

Hence required mass of B₄C is 55.25 grams.

To know more about stoichiometry, visit the below link:

brainly.com/question/25829169

#SPJ1

3 0

3 years ago

What is formed from nuclear decay? (2 points)

Anvisha [2.4K]

Answer:

Explanation:

A radioactive particle

7 0

3 years ago

How many moles of O2 are needed to react with 2.35 mol of C2H2?

Mrrafil [7]

2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

2.35 mol C2H2 - x mol O2
2 mol C2H2 - 5 mol O2

$x = \frac{2.35 \times 5}{2} = 5.875 \: mol$
answer: 5.875 mol

5 0

4 years ago

Read 2 more answers

Yeast and other organisms can convert glucose (C6H12O6) to ethanol (CH3CH2OH) by a process called alchoholic fermentation. The n

NISA [10]

Answer:

8.37 grams

Explanation:

The balanced chemical equation is:

C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)

Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.

From the ideal gas law we can determine the number of moles that the 2.25 L represent.

From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.

PV = nRT ⇒ n = PV/RT

n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂

Moles glucose required:

0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆

The molar mass of glucose is 180.16 g/mol, then the mass required is

0.046 mol x 180.16 g/mol = 8.37 g

5 0

3 years ago

Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)

marin [14]

Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

$S.G=\frac{D}{d_w}$

$d_w$ = density of water = 1 g/mL

$D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL$

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = $\frac{Mass}{Density}$

$=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L$

1 mL = 0.001 L

$Molarity = \frac{n}{V(L)}$

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

$Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L$

5 0

3 years ago