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Varvara68 [4.7K]
3 years ago
13

What does the subscript 2 indicate in the formula o2?

Chemistry
1 answer:
Tpy6a [65]3 years ago
6 0

The subscript 2 in the formula o2 indicates that there are 2 atoms of the element oxygen, represented by the symbol "O."   The subscript to the right of the symbol tells how many atoms are present of that element.  

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Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is
Citrus2011 [14]
Depression in freezing point (ΔT_{f}) = K_{f}×m×i,
where, K_{f} = cryoscopic constant = 1.86^{0} C/m,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For NaNO_{3})

Thus, (ΔT_{f}) = 1.86 X 0.0085 X 2 = 0.03162^{0}C

Now, (ΔT_{f}) = T^{0} - T
Here, T = freezing point of solution
T^{0} = freezing point of solvent = 0^{0}C
Thus, T = T^{0} - (ΔT_{f}) = -0.03162^{0}C
8 0
3 years ago
Read 2 more answers
Pregnant women are often cautioned against cleaning cat litter boxes. This is because Toxoplasma, an intestinal parasite of cats
Kryger [21]

Answer:

A communicable disease

Explanation:

Diseases that can be transferred are known as communicable diseases.

5 0
2 years ago
Where do the protons and electrons come from that are used in the electron transport chain?
blondinia [14]
The energy generated by the movement of electrons is used to pump electrons across the inner mitochondrial membrane to an area of higher concentration. 17. Where do these protons (H+) come from? The originally came from a glucose molecule and were carried to the electron transport chain by NADH and FADH2.

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5 0
3 years ago
N2 + 3H2 = 2NH3
My name is Ann [436]
This is so basic bro u gotta first move
6 0
3 years ago
If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?
Aleonysh [2.5K]

Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

M(N2) = 2*14 = 28 g/mol

M(NH3) = 14 + 3*1 = 17 g/mol

23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

                                 3H2 + N2 ------> 2NH3

from reaction         3 mol    1 mol

given                   11.8 mol    1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

                                 3H2 + N2 ------> 2NH3

from reaction                     1 mol         2 mol

given                                 1.01 mol      x

x = 2*1.01/1= 2.02 mol NH3

2.02 mol * 17g/1 mol ≈ 34.3 g NH3

8 0
3 years ago
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