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aksik [14]
3 years ago
13

Is Columns of elements in the periodic table are called periods correct in the underlined sentence

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
6 0
I don't know sorry I really need point
You might be interested in
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
Balance the following equation. Then determine the ratio for the products KCl and O2 generated during the decomposition of potas
drek231 [11]
The answer is 2:3 for plato users

6 0
2 years ago
Read 2 more answers
Sierra has a special kind of liquid rubber. She knows that ultraviolet light is
lana66690 [7]

Answer:

See explanation

Explanation:

Light is a form of energy. Both ultraviolet light and xrays are part of the electromagnetic spectrum.

As was said in the question, ultraviolet rays is absorbed by the rubber. We must know that prolonged exposure of this piece of rubber to incident ultraviolet light causes the vaporization of volatile materials in the rubber.

When volatile materials in the rubber vaporize, the rubber can become solid. Thus, ultraviolet light can cause rubber to become solid.

However, not all types of light can do this hence it does matter the type of light that falls on the rubber material.

8 0
3 years ago
The true absorbance for a 1.0 x 10 −5 M solution is 0.7526. If the percentage stray light for a spectrophotometer is 0.56%, calc
Korvikt [17]

Answer:

The percentage deviation is  \Delta M = 1.87%

Explanation:

From the question we are told that  

     The concentration is of the solution is C = 1.0*10^{-5} M

     The true absorbance A = 0.7526

      The percentage of transmittance due to stray light z = 0.56% =\frac{0.56}{100}  = 0.0056

Generally Absorbance is mathematically represented as

           A = -log T

Where T is  the percentage of true transmittance

    Substituting value  

          0.7526 = - log T

              T = 10^{-0.7526}

                  = 0.177

                  = 17.7%

The Apparent absorbance is mathematically represented

           A_p = -log (T +z)

Substituting values

           A_p = -log(0.177 + 0.0056)

                = -log(0.1826)

               = 0.7385

The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as

       \Delta A = \frac{A -A_p}{A} * \frac{100}{1}

              = \frac{0.7526 - 0.7385}{0.7526} * \frac{100}{1}

             \Delta A = 1.87%  

Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration  is

              \Delta M = 1.87%

           

6 0
3 years ago
Calculate the mass of carbon dioxide released when 185.000 g of copper carbonate [molar mass = 123.5 g/mol] is heated (assuming
Vinvika [58]

Answer:

The answer to your question is: 65.9 g released of CO2

Explanation:

MW CO2 = 44 g

MW CuCO3 = 123.5 g

CO2 released = ?

CuCO3 = 185 g

                            CuCO3     ⇒    CO2   +    CuO

                             123.5  -----------  44g

                             185 g -----------    x

                           x = (185 x 44) / 123.5

                           x = 65.9 g released of CO2

8 0
2 years ago
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