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Nikitich [7]
3 years ago
13

What would limit the population growth of rabbits in a forest ecosystem?

Chemistry
1 answer:
mihalych1998 [28]3 years ago
5 0
Other predators? or other factors that affect the food chain ie extinction of whatever source the rabbits feed off of
You might be interested in
Which compound contains ionic bonds? <br> 1) N2O<br> 2) Na2O<br> 3) CO<br> 4) CO2
lakkis [162]

Answer:

The ionic bond present between CaO molecule

Explanation:

7 0
2 years ago
If normal rainfall has a pH of 6.2 and acid rain has a pH of 2.8, how much greater is the hydrogen ion concentration of the acid
Ymorist [56]

Taking into account the definition of pH, the hydrogen ion concentration of the acid rain is 1.58×10⁻³ greater compared to normal rainfall.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Normal rainfall</h3>

Normal rainfall has a pH of 6.2. Replacing in the definition of pH:

6.2= - log [H⁺]

Solving:

[H⁺]= 10⁻⁶ ²

<u><em>[H⁺]= 6.31×10⁻⁷</em></u>

<h3>Acid rain</h3>

Acid rain has a pH of 2.8. Replacing in the definition of pH:

2.8= - log [H⁺]

Solving:

[H⁺]= 10⁻² ⁸

<u><em>[H⁺]= 1.58×10⁻³</em></u>

<h3>Hydrogen ion concentration difference of acid rain compared to normal rain.</h3>

To know how much greater is the hydrogen ion concentration of the acid rain compared to normal rainfall, you must do the subtraction between both concentrations:

1.58×10⁻³ - 6.31×10⁻⁷= 1.58×10⁻³

It is practically equal to the concentration of hydrogen ions in acid rain because its concentration is much higher than the concentration in normal rainfall.

In summary, the hydrogen ion concentration of the acid rain is 1.58×10⁻³ greater compared to normal rainfall.

Learn more about pH:

brainly.com/question/12200689

8 0
2 years ago
What is the concentration (M) of sodium ions in 4.57 L of a .398 M Na3P solution?
steposvetlana [31]

 The   concentration   of sodium  ion  is  1.194 M


 <u><em>calculation</em></u>

 Step 1:  write  the equation for  dissociation  of Na₃P

Na₃P  →  3 Na⁺(aq)  + P⁻ (aq)

  Step  2:  find the  moles of  Na₃p

MOLES =  molarity  x volume in liters

 =  4.57 L  x  0.398  M = 1.819  moles

Step 3:  use  the  mole ratio to calculate the  moles of  Na⁺

Na₃P: Na⁺  is   1:3  therefore the  moles of Na⁺  =   3  x 1.819  = 5.457  moles

Step  4 :  find  the concentration (molarity)  of Na⁺

molarity  =  moles /volume in liters

=5.457  moles / 4.57 = 1.194 M

8 0
3 years ago
Read 2 more answers
7. Convert 158 g of C to moles.​
LuckyWell [14K]

Answer:

Number of mole = 13.155moles

Explanation:

One mole of a substance is equal to 6.022 * 10^23 units of that substance.

Mole of a substance can be defined according to chemistry as the mass of substance containing the same number of fundamental units

Using the formula for mole

n = m/Mm

n = number of mole

m = number of mass

Mm = number of molar mass

We are provided with some information

Given: mass of carbon to be 158g

Molar mass of C = 12.0107g/mol

Using the formula

n = m/Mm

n = 158 / 12.0107

n = 13.155 moles

3 0
3 years ago
A wooden block has a length of 4.0 cm, a width of 2.0 cm, and a height of 1.0 cm. What is the volume of this block?
MakcuM [25]
Use the formula for volume. V = lwh. Plug in the numbers for length, width, and height. Now we have V = 4.0 x 2.0 x 1.0, which is 8.0. So the volume of the block is 8.0 cm.

Thanks for your question! Don't forget to rate and give me the brainliest answer! Then, I can help you with all your problems! ^-^ ~
8 0
3 years ago
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