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nalin [4]
4 years ago
13

Two objects of same material are travelling near you. Object A is a 1.9 kg mass traveling 8 m/s; object B is a 2 kg mass traveli

ng 5 m/s. Which object would make you feel worse if you are hit by it?
1. B
2. the same
3. Unable to determine
4. A
Physics
1 answer:
Alex73 [517]4 years ago
3 0

To determine the object which could give the greatest impact we will apply the concept of momentum. The object that has the highest momentum will be the object that will impact the strongest. Our values are

Mass of Object A

m_A=1.9 kg

Velocity of object A

v_A=8ms

Mass of object B

m_B=2 kg

Velocity of object B

v_B=5ms

The general formula for momentum is the product between mass and velocity, then

p = mv

For each object we have then,

p_A=m_Av_A=1.9 kg(8ms)=15.2kg \cdot m/s

p_B=m_Bv_B=2 kg(5ms)=10kg \cdot m/s

Since the momentum of object A is greater than that of object B, then object A will make you feel force upon impact.

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A device called an insolation meter is used to measure the intensity of sunlight. It has an area of 100 cm2 and registers 6.50 W
labwork [276]

Answer:

<h2>650W/m²</h2>

Explanation:

Intensity of the sunlight is expressed as I  = Power/cross sectional area. It is measured in W/m²

Given parameters

Power rating = 6.50Watts

Cross sectional area = 100cm²

Before we calculate the intensity, we need to convert the area to m² first.

100cm² = 10cm * 10cm

SInce 100cm = 1m

10cm = (10/100)m

10cm = 0.1m

100cm² = 0.1m * 0.1m = 0.01m²

Area (in m²) = 0.01m²

Required

Intensity of the sunlight I

I = P/A

I = 6.5/0.01

I = 650W/m²

Hence, the intensity of the sunlight in W/m² is 650W/m²

4 0
3 years ago
People hoping to travel to other worlds are faced with huge challenges. One of the biggest is the time required for a journey. T
Dafna11 [192]

Answer:

The travel would take 6.7 years.

Explanation:

The equation for an object moving in a straight line with acceleration is:

x = x0 + v0 t + 1/2a*t²

where:

x = position at time t

x0 = initial position

v0 = initial velocity

a = acceleration

t = time

In a movement with constant speed, a = 0 and the equation for the position will be:

x = x0 + v t

where v = velocity

Let´s calculate the position from the Earth after half a year moving with an acceleration of 1.3 g = 1.3 * 9.8 m/s² = 12.74  m/s²:

Seconds in half a year:

1/2 year = 1.58 x 10⁷ s

x = 0 m + 0 m/s + 1/2 * 12.74 m/s² * (1.58 x 10⁷ s)²  = 1.59 x 10¹⁵ m

Now let´s see how much time it takes the travel to the nearest star after this half year.

The velocity will be the final velocity achived after the half-year travel with an acceleration of 12.74 m/s²

v = v0 + a t

Since the spacecraft starts from rest, v0 = 0

v = 12.74 m/s² * 1.58 x 10⁷ s = 2.01 x 10 ⁸ m/s

Using the equation for position:

x = x0 + v t

4.1 x 10¹⁶ m = 1.59 x 10¹⁵ m + 2.01 x 10 ⁸ m/s * t

(4.1 x 10¹⁶ m - 1.59 x 10¹⁵ m) / 2.01 x 10 ⁸ m/s = t

t = 2.0 x 10⁸ s * 1 year / 3.2 x 10 ⁷ s = 6.2 years.

The travel to the nearest star would take 6.2 years + 0.5 years = 6.7 years.

7 0
3 years ago
In which scenario is the greatest amount of work done on a wagon?
ale4655 [162]

Answer:

The first scenario!

Explanation:

W=F*d

a) 55*8= 440J

b) 60*6= 360J

c) 50*5= 250J

d) 40*10= 400J

5 0
3 years ago
Read 2 more answers
A uniform steel of density 7800 kg/m³ weight 16g and is 250cm long .It is lengthens by 1.2mm when a force of 80N is applied.
Harlamova29_29 [7]

Explanation:

<em>hopes </em><em>it's </em><em>h</em><em>elped </em><em>uh </em><em>mate</em><em>!</em>

4 0
3 years ago
A 0.23 kg ladle sliding on a horizontal frictionless surface is attached to one end of a horizontal spring (k = 580 N/m) whose o
Anna71 [15]

Answer:

Explanation:

Angular speed of the motion ( SHM )

ω = √k/m

= √(580/.23 )

= 50.20 radian /s

a ) Rate of doing work

= power = force x velocity

At the equilibrium position force becomes zero so

rate of doing work is zero.

b )

If a be the amplitude

1/2 k a² = 170

a = .7655 m

kinetic energy at equilibrium = 1/ 2 m v₀²

1/ 2 m v₀² = 170

.5 x  23  v₀² = 170

v₀ = 3.84 m /s which is the maximum velocity.

Given x = .66 where rate of doing work is to be calculated.

Force at x = ω² x

= 50.20² x .66 =

= 1663.22 N

Velocity v = v₀ √( a² - x² )

= 3.84 √( .7655² - .66 )

= 3.84 x .387

= 1.486 m/s

power = force x velocity

=  1663.22 x 1.486

= 2471.55  W .

3 0
3 years ago
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