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3 years ago

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Two objects of same material are travelling near you. Object A is a 1.9 kg mass traveling 8 m/s; object B is a 2 kg mass traveli

ng 5 m/s. Which object would make you feel worse if you are hit by it?
1. B
2. the same
3. Unable to determine
4. A

1 answer:

Alex73 [517]3 years ago

3 0

To determine the object which could give the greatest impact we will apply the concept of momentum. The object that has the highest momentum will be the object that will impact the strongest. Our values are

Mass of Object A

$m_A=1.9 kg$

Velocity of object A

$v_A=8ms$

Mass of object B

$m_B=2 kg$

Velocity of object B

$v_B=5ms$

The general formula for momentum is the product between mass and velocity, then

$p = mv$

For each object we have then,

$p_A=m_Av_A=1.9 kg(8ms)=15.2kg \cdot m/s$

$p_B=m_Bv_B=2 kg(5ms)=10kg \cdot m/s$

Since the momentum of object A is greater than that of object B, then object A will make you feel force upon impact.

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dalvyx [7]

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1) (2.68 x 10¯5) x (4.40 x 10¯8)

The calculator display gives 1.1792 x 10¯12. Rounded off to three significant figures gives 1.18 x 10¯12 as the answer.

2) (2.95 x 107) ÷ (6.28 x 1015)

The calculator display gives 4.6975 x 10¯9. Rounded off to three significant figures gives 4.70 x 10¯9 as the answer.

3) (8.41 x 106) x (5.02 x 1012)

The calculator display gives 4.2218 x 1019. Rounded off to three significant figures gives 4.22 x 1019 as the answer.

When done as a division, the answer to this problem is 1.68 x 10¯6.

4) (9.21 x 10¯4) ÷ (7.60 x 105)

The calculator display gives 1.2118 x 10¯9. Rounded off to three significant figures gives 1.21 x 10¯9 as the answer

7 0

2 years ago

What is the net charge of a metal ball if there are 21,749 extra electrons in it?

pickupchik [31]

Answer:

$Q=3.47\times 10^{-15}\ C$

Explanation:

Given that,

Number of extra electrons, n = 21749

We need to find the net charge on the metal ball. Let Q is the net charge.

We know that the charge on an electron is $q=1.6\times 10^{-19}\ C$

To find the net charge if there are n number of extra electrons is :

Q = n × q

$Q=21749\times 1.6\times 10^{-19}\ C$

$Q=3.47\times 10^{-15}\ C$

So, the net charge on the metal ball is $3.47\times 10^{-15}\ C$ . Hence, this is the required solution.

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3 years ago

A car is driving at 50 kilometers per hour. how far, in meters, does it travel in 2 seconds?

AveGali [126]

<span>Sure, Just change the 2 sec. into hrs. Since 1 hour = 3600 sec. then you can divide 2/3600 = 1/1800 hrs. Distance in kilometers = (Speed in km/hr * time in hrs) = 50*(1/1800)*1000 in meters = 27.77 meters</span>

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2 years ago

A NASA satellite has just observed an asteroid that is on a collision course with the Earth. The asteroid has an estimated mass,

Citrus2011 [14]

Answer:

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So we will have

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now from above formula

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now we have

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now plug in all data

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Ivenika [448]

I think its A I hope this help thank you!!

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3 years ago