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nalin [4]
4 years ago
13

Two objects of same material are travelling near you. Object A is a 1.9 kg mass traveling 8 m/s; object B is a 2 kg mass traveli

ng 5 m/s. Which object would make you feel worse if you are hit by it?
1. B
2. the same
3. Unable to determine
4. A
Physics
1 answer:
Alex73 [517]4 years ago
3 0

To determine the object which could give the greatest impact we will apply the concept of momentum. The object that has the highest momentum will be the object that will impact the strongest. Our values are

Mass of Object A

m_A=1.9 kg

Velocity of object A

v_A=8ms

Mass of object B

m_B=2 kg

Velocity of object B

v_B=5ms

The general formula for momentum is the product between mass and velocity, then

p = mv

For each object we have then,

p_A=m_Av_A=1.9 kg(8ms)=15.2kg \cdot m/s

p_B=m_Bv_B=2 kg(5ms)=10kg \cdot m/s

Since the momentum of object A is greater than that of object B, then object A will make you feel force upon impact.

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Answer:

A) 588 pounds

Explanation:

According to the given conditions, we assume the beam to be simply supported at the ends carrying a uniformly distributed load of 125 pounds per feet and a point load of 600 pounds acting at 5 feet from the right support.

Referring the schematic:

<u>Moment about any point will be zero in equilibrium condition. </u>

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4 years ago
A single-turn circular loop of wire that has a radius of 3.5 cm lies in the plane perpendicular to a spatially uniform magnetic
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Explanation:

Given that,

Radius of the circular loop, r = 3.5 cm = 0.035 m

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\epsilon=-\dfrac{d(BA)}{dt}\\\\\epsilon=-\pi r^2\dfrac{B_f-B_i}{dt}\\\\\epsilon=-\pi (0.035)^2\dfrac{0.5-0.2}{0.12}\\\\\epsilon=-9.62\times 10^{-3}\ volts

So, the magnitude of the emf induced in the loop during the time interval is 9.62\times 10^{-3}\ V.

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Calculate the ratio of the drag force on a passenger jet flying with a speed of 1200 km/h at an altitude of 10 km to the drag fo
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Answer:

2.267

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F=\dfrac{1}{2}\rho Av^2C

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A = Area is constant

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v_2 = Velocity of the prop plane = \dfrac{1}{4}v_1

\rho_1 = Density of the air where the jet was flying = 0.38\ \text{kg/m}^3

\rho_2 = Density of the air where the prop plane was flying = 0.67\ \text{kg/m}^3

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\dfrac{F_1}{F_2}=\dfrac{\rho_1 v_1^2}{\rho_2 v_2^2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{0.38 v_1^2}{0.67 (\dfrac{1}{4}v_1^2)}\\\Rightarrow \dfrac{F_1}{F_2}=2.267

The ratio of the drag forces is 2.267.

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