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nalin [4]
4 years ago
13

Two objects of same material are travelling near you. Object A is a 1.9 kg mass traveling 8 m/s; object B is a 2 kg mass traveli

ng 5 m/s. Which object would make you feel worse if you are hit by it?
1. B
2. the same
3. Unable to determine
4. A
Physics
1 answer:
Alex73 [517]4 years ago
3 0

To determine the object which could give the greatest impact we will apply the concept of momentum. The object that has the highest momentum will be the object that will impact the strongest. Our values are

Mass of Object A

m_A=1.9 kg

Velocity of object A

v_A=8ms

Mass of object B

m_B=2 kg

Velocity of object B

v_B=5ms

The general formula for momentum is the product between mass and velocity, then

p = mv

For each object we have then,

p_A=m_Av_A=1.9 kg(8ms)=15.2kg \cdot m/s

p_B=m_Bv_B=2 kg(5ms)=10kg \cdot m/s

Since the momentum of object A is greater than that of object B, then object A will make you feel force upon impact.

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Answer:

The radius of the cable is 0.0083 m or 8.3 mm.

Explanation:

The resistance of copper cable of 1 meter length will be given by

R_{cable} = \frac{\rho \times l}{a}    ....     (i)

where the resistivity of copper is \rho = 1.7 \times 10^{-8} \Omega.m , and l is the length of the wire which is considered to be 1m, and a is the cross sectional area of the wire in m^{2}.

From the formula of power we know that, P = I^2 R    ....    (ii)

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where  the resistance,R, actually means the resistance of the cable per meter.

Therefore R ( resistance of cable per meter)

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Therefore from (i)

7.812 \times 10^{-5} = \frac{1.7 \times 10^{-8} \times 1}{a}  = \frac{1.7 \times 10^{-8} \times 1}{\pi r^{2} }       .....     (v)

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where r is the radius of the cable, and length of cable,l = 1m.

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The potential energy per unit volume is defined as the energy density.

u = \frac{U}{V}

u= \frac{(13.0 J)}{(6.00*10^{-9} m^3)}

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