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cestrela7 [59]
3 years ago
5

What is the correct answer?

Physics
1 answer:
katen-ka-za [31]3 years ago
4 0
Red line -1 because it is just starting out and climbing speed so his energy is at lowest hopefully this helps
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Which occurs at a transform boundary?
andreev551 [17]
The answer is B. One plate slides past another. 

The San Andreas Fault in California and the Alpine Fault in New Zealand are examples of transform boundaries. 

Hope this helps! :)
5 0
3 years ago
The voltage across the terminals of a 9.0 v battery is 8.5 v when the battery is connected to a 60 ω load. part a what is the ba
snow_lady [41]
Refer to the diagram shown below.

i = the current in the circuit., A
R₁ = the internal resistance of the battery, Ω
R₂ = the resistance of the 60 W load, Ω

Because the resistance across the battery is 8.5 V instead of 9.0 V, therefore
(R₁ )(i A) = 9 - 8.5 = (0.5 V)
R₁*i = 0.5         (10

Also,
R₂*i = 9.5         (2)

Because the power dissipated by R₂ is 60 W, therefore
i²R₂ = 60
From (2), obtain
i*9.5 = 60
i = 6.3158 A

From (1), obtain
6.3158*R₁ = 0.5
R₁ = 0.5/6.3158 = 0.0792 Ω = 0.08 Ω (nearest hundredth)

Answer: 0.08 Ω

3 0
3 years ago
Read 2 more answers
Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They
mamaluj [8]

Answer:

Explanation:

a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s.

F = M x 48

Mass M = F / 48

a )

When force = 2F and mass = M

Acceleration = force / mass

= 2F /F/48

= 48 X 2 = 96 cm/s²

b )

When force = F and mass = 2M

Acceleration = force / mass

= F /2F/48

=  24 cm/s²

c )

When force = 2F and mass = 2M

Acceleration = force / mass

= 2F /2F/48

=  48  cm/s

d )

When force = 2F and mass = 4M

Acceleration = force / mass

= 2F /4F/48

=  24  cm/s

e)

When force = 4F and mass = 2M

Acceleration = force / mass

= 4F / 2M

= 4F / 2 F/48

= 48 x 2

Acceleration  = 96 cm/s²

7 0
4 years ago
How much work is done by the force of gravity when the book is released?
Naya [18.7K]

Answer:

please see picture

Explanation:

and mark me brainliest

3 0
3 years ago
A car of mass 1200Kilograms moving at 15 m/s the driver applies the brakes for 0.08 seconds and the castles down to 10 meter per
denpristay [2]
  • Initial velocity=u=15m/s
  • Final velocity=v=10m/s
  • Time=0.08s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{10-15}{0.08}

\\ \sf\longmapsto Acceleration=\dfrac{-5}{0.08}

\\ \sf\longmapsto Acceleration=-62.5m/s^2

5 0
3 years ago
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