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cestrela7 [59]
2 years ago
5

What is the correct answer?

Physics
1 answer:
katen-ka-za [31]2 years ago
4 0
Red line -1 because it is just starting out and climbing speed so his energy is at lowest hopefully this helps
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The moon's orbit around the Earth will advance in one day:<br><br> 1°<br> 13°<br> 27°<br> 29°
Sever21 [200]
<span>The moon's orbit around the Earth will advance in one day:

1°
13° correct answer 
27°
29°</span><span />
3 0
3 years ago
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From the average distance of one of jupiter's moons to jupiter and its orbital period around jupiter, we can determine:
den301095 [7]

Answer: Jupiter's mass

Explanation:

From Kepler's third law:

T^2=\frac{4\pi^2}{GM}a^3

where T is the orbital period of a satellite, a is the average distance of the satellite from the Planet, M is the mass of the planet, G is the gravitational constant.

If the average distance of one of Jupiter's moons to Jupiter and its orbital period around Jupiter is given then mass of the Jupiter can be found:

\Rightarrow M_J=\frac{4\pi^2}{GT_m^2}a_m^3

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3 years ago
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How does increasing the distance between charged objects affect the electric force between them? the electric force increases be
konstantin123 [22]

the electric force decreases because the distance has an indirect relationship to the force

Explanation:

The electric force between two objects is given by

F=k \frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the distance between the two objects

As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.

3 0
3 years ago
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If the magnetic flux through a loop increases according to the relation; where , is in milliweber (mWb) and t is in seconds. Cal
Alekssandra [29.7K]

The magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

<h3>emf induced in the loop</h3>

The magnitude of e.m.f induced in the loop is calculated as follows;

emf = dФ/dt

Ф = 6t² + 7t

dФ/dt = 12t + 7

at t = 2 seconds

emf = dФ/dt = 12(2) + 7 = 31 V

Thus,  the magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

Learn more about emf here: brainly.com/question/24158806

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2 years ago
When a wire loop is connected to a battery, what is produced in the loop?
Vinil7 [7]

Answer:

magnetic field

Explanation:

3 0
3 years ago
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