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kolezko [41]
4 years ago
7

The Kyoto Protocol, which limits emissions of greenhouse gases for developed nations, is an example of which type of law? A. con

stitutional law B. criminal law C. international law D. common law
Physics
2 answers:
ser-zykov [4K]4 years ago
7 0

Answer:

C.International Law

Explanation:

The Kyoto Protocol is an international agreement to reduce carbon dioxide (CO2) emissions and the presence of greenhouse gases (GHG) in the atmosphere. The main principle of the Kyoto Protocol was that the industrialized countries should reduce the amount of their CO2 emissions.

The protocol was adopted in Kyoto, Japan in 1997 when greenhouse gases quickly threatened our climate, life on Earth and the planet itself. The Kyoto Protocol is still alive in many other ways today, and its problems are still under discussion.

The Kyoto Protocol urged industrialized countries to cut greenhouse gas emissions at a time when the risk of global warming was increasing rapidly. The protocol was linked to the United Nations Framework Convention on Climate Change (UNFCCC). It was adopted on December 11, 1997, in Kyoto, Japan, and on February 16, 2005, on international law.

bazaltina [42]4 years ago
6 0

The Kyoto Protocol, which limits emissions of greenhouse gases for developed nations, is an example of international Law

Explanation:

The Kyoto Protocol is named after a Japanese city in which it was executed in the year 1997 on 1st December.

The basic aim of the Kyoto Protocol is to reduce/Limit  the emission of greenhouse gases which contributed to  global warming

The Protocol was linked to the United Nations Framework Convention on Climate Change (UNFCCC)

The important factor that led to the failure of Kyoto's Protocol  are deficiencies in the structure of the agreement, such as the exemption of developing countries from reductions requirements, or the lack of an effective emissions trading scheme

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Answer: The Forces Between Protons at Nuclear Distances. Two protons are subject to two forces; the nuclear force and the electrostatic force. When they are very close together the nuclear force is dominant and when they are far apart it is the electrostatic force which is dominant.

Did that help?

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Submitting a résumé to a potential employer means you do not need to complete an employment application. TRUE FALSE
noname [10]
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how much centripetal force is needed to make a body of mass 0.5 kg to move in a circle of radius 50 cm with a speed 3ms-1
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9 N

Explanation:

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In this case, m = 0.5kg, r = 0.5m, v = 3m/s

So F = [0.5kg(3m/s)^2]/0.5m = 9kg-m/s^2 which is 9N

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Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

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3 years ago
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