Answer:
The electric and magnetic field are 6.34 N/C and
.
Explanation:
Given that,
Distance = 4.5 m
Time = 2.84 μs
We need to calculate the acceleration
Using equation of motion
The distance covered by the electron is
![s=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
When, the electron at rest
Where, s = distance
a = acceleration
t = time
Put the value into the formula
![4.5=\dfrac{1}{2}\times a\times(2.84\times10^{-6})^2](https://tex.z-dn.net/?f=4.5%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%282.84%5Ctimes10%5E%7B-6%7D%29%5E2%20)
![a=\dfrac{2\times4.5}{(2.84\times10^{-6})^2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B2%5Ctimes4.5%7D%7B%282.84%5Ctimes10%5E%7B-6%7D%29%5E2%7D)
![a=1.116\times10^{12}\ m/s^2](https://tex.z-dn.net/?f=a%3D1.116%5Ctimes10%5E%7B12%7D%5C%20m%2Fs%5E2)
We need to calculate the electric field
Using formula of the electric field
![E=\dfrac{F}{q}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BF%7D%7Bq%7D)
![E=\dfrac{ma}{q}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bma%7D%7Bq%7D)
Put the value into the formula
![E=\dfrac{9.1\times10^{-31}\times1.116\times10^{12}}{1.6\times10^{-19}}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B9.1%5Ctimes10%5E%7B-31%7D%5Ctimes1.116%5Ctimes10%5E%7B12%7D%7D%7B1.6%5Ctimes10%5E%7B-19%7D%7D)
![E=6.34\ N/C](https://tex.z-dn.net/?f=E%3D6.34%5C%20N%2FC)
We need to calculate the magnetic field
Using formula of magnetic field
![B = \dfrac{E}{c}](https://tex.z-dn.net/?f=B%20%3D%20%5Cdfrac%7BE%7D%7Bc%7D)
Put the value into the formula
![B=\dfrac{6.34}{3\times10^{8}}](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7B6.34%7D%7B3%5Ctimes10%5E%7B8%7D%7D)
![B=2.11\times10^{-8}\ T](https://tex.z-dn.net/?f=B%3D2.11%5Ctimes10%5E%7B-8%7D%5C%20T)
According to the right hand rule,
The direction of magnetic field is outward because the direction of force is upward.
Hence, The electric and magnetic field are 6.34 N/C and
.