Answer:
Rate = 43 M⁻¹s⁻¹[NO₂][O₃]
Explanation:
We need to find the reaction order in
rate = (NO₂ )ᵃ (O₃ )ᵇ
given:
( NO₂ ) M ( O₃ ) M Rate M/s
0.10 0.33 1.420 (1)
0.10 0.66 2.840 (2)
0.25 0.66 7.10 (3)
When keeping the NO₂ concentration constant in the first two while doubling the concentration of O₃ , the rate doubles. Therefore it is first order with respect to O₃
Comparing (2) and (3) increasing the concentration of NO₂ by a factor of 2.5 and keeping O₃ constant , increased the rate by a factor of 2.5. Therefore the rate is first order with respect to NO₂
Then rate law is
= k (NO₂) (O₃ )
To find k take any of the three and substitute the values to find k:
1.420 M/s = k (0.10)M x (0.33)M ⇒ k = 43 /Ms
Then the answer is Rate = 43 M⁻¹s⁻¹[NO₂][O₃]
Answer:
Biochemistry focuses on the studies of biological matter. ... Medical biochemistry seeks to advance the understanding of chemical structures and processes that constitute health and disease, and underlie transformations between these two states.
The energy increases because the molecules in water move faster
Answer:
C. molecules
Explanation:
Since, the temperature, pressure and volume conditions are same, the molecules of ammonia gas must be equal to the molecules of the argon according to the ideal gas equation which is shown below as:-
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Thus, both will have same moles and same number of molecules.
<u>Thus, molecules of argon = molecules</u>
<u>Answer: </u>One isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.
<u>Explanation:</u>
We are given the two stable isotopes of chlorine with their respective masses. The average atomic mass of chlorine is also given.
Average atomic mass of chlorine = 35.45 amu.
Let us assume the fractional abundance of one isotope be 'x' and the fractional abundance for another isotope will be (1 - x) because the total fractional abundance is always equal to 1.
Fractional abundance = x
Mass = 34.97 amu
Fractional abundance = 1 - x
Mass = 36.95 amu
The formula for the calculation of average atomic mass is given by:
Putting values in above equation, we get:
Converting these two fractional abundances into percentage abundances by multiplying it with 100.
Hence, one isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.