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Semmy [17]
3 years ago
7

Which of the following is a unit of length? O A. A liter O B. A kilogram C. A meter O D. A degree​

Chemistry
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

C.) A meter

Explanation:

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ASAP something that flows into a substance
Radda [10]

Answer:

can oxygen exist as a liquid and solid

7 0
2 years ago
If a gas at 25oC occupies 3.60 L at a pressure of 2.50 atm, what will be its volume at a pressure of 1.00 atm if the temperature
Elenna [48]

Answer:

9L

Explanation:

Given parameters:

Initial volume V₁ = 3.6L

Initial pressure P₁  = 2.5atm

Final pressure P₂  = 1atm

Unknown:

Final volume V₂  = ?

Condition: constant temperature  = 25°C

Solution:

This problem compares the volume and pressure of a gas at constant temperature.

This is highly synonymous to the postulate of Boyle's law. It states that "the volume of a fixed mass of gas is inversely proportional to the pressure provided that temperature is constant".

Mathematically;

              P₁V₁  = P₂V₂

where P and V are pressure and volume

          1 and 2 are initial and final states

Input the parameters and solve for V₂;

          2.5 x 3.6  = 1 x V₂

                  V₂  = 9L

4 0
3 years ago
True or False <br>sound needs a medium to travel​
astra-53 [7]

Answer:

True or T

Explanation:

Is the correct answer please make me brainliest

5 0
2 years ago
Read 2 more answers
molecules of i2 are produced by the reaction of 0.4321 mol of cucl2 according to the following equation. 2 cucl2 4 ki → 2 cui 4
Juli2301 [7.4K]

\: 1.237 \times 10^{23}   molecules \: of \:I _{2} \: are

are\: produced \: and \: 53.74 \: g \: of \: I _{2} \: are

produced from the reaction.

The overall balanced equation for the reaction is,

2CuCl_{2} +   KI→2CuI + 4KCl  + I_{2}

Number  \: of  \: moles  \: ofCuCl_{2}=0.4235 \: mol

2 \: moles \: of \: CuCl_{2} \: produce \: \: 1 \: mole \:

of \:  I_{2}.

2 \: mole \: of \: CuCl_{2}  = 1 \: mole \: of \:  I_{2}

1 \: mole \: of \: I_{2} \:  = 6.022 \times 10 ^{23}  \: molecules \: of  I_{2}

So, the number of molecules produced in the reaction of

I_{2} \: are

=  \frac{0.4235 \times 6.022 \times 10 ^{23} }{2 }

= 1.237 \times 10^{23}  \: molecules \:

1.237 \times 10^{23}  \: molecules \: of \: I_{2} \: are \:

produced from the reaction.

Mass  \: of \:   I _{2} \: produced \: are \: is ,

=  \frac{0.4235 \times 253.8}{2}

= 53.74 \: g

53.74 \: g \: of \:  I _{2} \: produced \: in \: the \:

reaction.

Therefore , \: 1.237 \times 10^{23}   molecules

of  \: I_{2} \: are\: produced \: and \: 53.74 \: g \: of

are produced in the reaction.

To know more about moles, refer to the below link:

brainly.com/question/26416088

#SPJ4

7 0
2 years ago
What happens to a reaction at equilibrium when a product is removed from the reaction system?
adoni [48]
C. the reaction is unchanged.
5 0
3 years ago
Read 2 more answers
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