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sukhopar [10]
3 years ago
12

#5 A pair of jeans was 30% off the

Mathematics
1 answer:
just olya [345]3 years ago
8 0

Answer:

80

Step-by-step explanation:

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Help please! ill mark brainliest!
Natasha_Volkova [10]

Answer:

0.225989

Step-by-step explanation:

3x+9+x-11=180

4x-3=180

4x=180-3

4x/4x=177/4x

0.225989

7 0
3 years ago
Read 2 more answers
Explain how to find a common denominator of 3/4 and 1/5 what is a common denominator of 3/4 and 1/5 show how you can rename 3/4
Paul [167]

Answer:

Common denominator = 20

New fractions are: \dfrac{15}{20}\ and\ \dfrac{4}{20}

Step-by-step explanation:

Given:

The fractions are given as:

\dfrac{3}{4}\ and\ \dfrac{1}{5}

The denominators of the first fraction is 4 and that of the second fraction is 5.

In order to find the common denominator for 4 and 5, we have to find the least common multiple of each of the numbers.

Multiples of 4 = 4, 8, 12, 16, <u>20</u>, 24, 28,....

Multiples of 5 = 5, 10, 15, <u>20</u>, 25, 30,....

Therefore, the least common multiple of 4 and 5 is 20. So, the common denominator is 20.

Now, multiply the numerator and denominator of each fraction by the same suitable number such that the denominator becomes 20.

So, for the first fraction, 4 is in the denominator.

So, 4 when multiplied by 5 gives 20.

So, we multiply the numerator and denominator of first fraction by 5. This gives,

\dfrac{3}{4}=\dfrac{3\times 5}{4\times 5}=\dfrac{15}{20}

Now, for the second fraction, 5 is in the denominator.

So, 5 when multiplied by 4 gives 20.

So, we multiply the numerator and denominator of first fraction by 4. This gives,

\dfrac{1}{5}=\dfrac{1\times 4}{5\times 4}=\dfrac{4}{20}

Therefore, the new fractions after making the denominators same are:

\dfrac{15}{20}\ and\ \dfrac{4}{20}

4 0
3 years ago
Explain why the "+ C" is not needed in the antiderivative when evaluating a definite integral.
Aliun [14]

The reason the "+ C" is not needed in the antiderivative when evaluating a definite integral is; The C's cancel each other out as desired.

<h3>How to represent Integrals?</h3>

Let us say we want to estimate the definite integral;

I = \int\limits^a_b {f'(x)} \, dx

Now, for any C, f(x) + C is an antiderivative of f′(x).

From fundamental theorem of Calculus, we can say that;

I = \int\limits^a_b {f'(x)} \, dx  = \phi(a) - \phi(b)

where Ф(x) is any antiderivative of f'(x). Thus, Ф(x) = f(x) + C would not work because the C's will cancel each other.

Read more about Integrals at; brainly.com/question/22008756

#SPJ1

8 0
1 year ago
4. Identify the graph of the solution set of 9 &gt; 3 + 2x.
Ray Of Light [21]

Answer:

A

Step-by-step explanation:

9 > 3 + 2x

6 > 2x

3 > x

or

x < 3

and that means 3 is NOT included (otherwise there must be a smaller or equal sign). hence A is the right answer.

7 0
2 years ago
How to find the inverse of a function
Studentka2010 [4]
Switch the x and the y and solve for y 
eg inverse of 2y= 3x+1
swith x and y
2x=3y+1
now solve for y
y =(2x-1)/3
5 0
3 years ago
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