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2 years ago

Which statements about energy are true?

Physics

2 answers:

Masteriza [31]2 years ago

7 0

Answer:

i think that the awnsre is d

vampirchik [111]2 years ago

4 0

Answer:

Explanation:

this is because i need more words

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Derive the kinetic equations for Vmax and KM using the transit time and net rate constant method as discussed in class and follo

Pepsi [2]

Answer:

Rate = vmax k3/k2+k3

Explanation:

The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, is referred to as Vmax.

This is usually expressed as the Km ie. Michaelis constant of the enzyme, an inverse measure of affinity. For practical purposes, Km is the concentration of substrate which permits the enzyme to achieve half Vmax.

Please kindly check attachment for the step by step solution of the given problem.

6 0

2 years ago

Block 1 (mass 2.00 kg) is moving rightward at 10.0 m/s and block 2 (mass 5.00 kg) is moving rightward at 3.00 m/s. The surface i

DaniilM [7]

Answer:

a) 0.25m

b) 5 m/s

Explanation:

When the spring is compressed both boxes are moving with the same velocity, so applying the principle of linear momentum conservation:

$m1*v_{o1}+m2*v_{o2}=(m1+m2)*v\\v=5m/s$

Now applying the principle of energy conservation:

$K1+K2+U_{g1}-U_e=Kf+U_{g2}\\K1+0-U_e=K2+0\\U_e=K1+K2-kf\\\frac{1}{2}*k*x^2+=\frac{1}{2}*m1*v1^2+\frac{1}{2}*m1*v1^2-\frac{1}{2}*(m1+m2)*v^2\\\\x=\sqrt{\frac{2.00kg*(10m/s)^2+5.00kg*(3.00m/s)^2-7.00kg*(5m/s)^2}{1120N/m}}\\x=0.25m$

We got that the maximum compression is 0.25m.

5 0

2 years ago

Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 x 10-11 m, the expected

V125BC [204]

Would be A 1012 N/C because The magnitude of the electric field at distance r from a point charge q is E=k
e

q/r
2
, so
E=
(5.11×10
−11
m)
2

(8.99×10
9
N.m
2
/C
2
)(1.60×10
−19
C)

=5.51×10
11
N/C∼10
1
2N/C
making (e) the best choice for this question.

3 0

3 years ago

(4 points) A mother with mass m1 is skating at velocity v1 behind her daughter whose mass is m2, who is skating at v2 . Instead

STatiana [176]

Answer:

B) collision is inelastic because they stick together after collision and share a common final velocity Vf

C) M1V1 + M2V2 = (M1 + M2)Vf

D) Vf = 6.33m/s

E) force = 3040N

Explanation:

Detailed explanation and calculation is shown in the image below

3 0

2 years ago

A 36-g ball at the end of a string is swung in a vertical circle with a radius of 19 cm. The tangential velocity is 200.0 cm/s.

STALIN [3.7K]

Answer:

0.758 N

Explanation:

mass of ball, = 36 g = 0.036 kg

radius, r = 19 cm = 0.19 m

tangential velocity, v = 200 cm / s = 2 m /s

The tension is the string is equal to the centripetal force acting on the ball.

The centripetal force acting on the ball is given by

$T=\frac{mv^{2}}{r}$

$T=\frac{0.036 \times 2 \times 2}{0.19}$

T = 0.758 N

Thus, the tension in the string is given by 0.758 N.

7 0

3 years ago